我尝试通过 GDI 创建填充和橡皮擦工具，但这种方式对于 Windows 手机设备来说太慢了，并且使用这种方法处理大照片对于这些设备来说太难了。我搜索替代解决方案并Image Processing找到但不确定这些 Api 是否可以帮助我创建这些工具。Win2DSharpdx
这是填写工具winrtxamltoolkit
public static void FloodFill(this WriteableBitmap target, int x, int y, int outlineColor, int fillColor, byte maxdiff)
{
var width = target.PixelWidth;
var height = target.PixelHeight;
var queue = new List<Pnt>();
using (var context = target.GetBitmapContext(ReadWriteMode.ReadWrite))
{
queue.Add(new Pnt { X = x, Y = y });
while (queue.Count > 0)
{
var p = queue[queue.Count - 1];
queue.RemoveAt(queue.Count - 1);
if (p.X == -1) continue;
if (p.X == width) continue;
if (p.Y == -1) continue;
if (p.Y == height) continue;
if (context.Pixels[width * p.Y + p.X] == outlineColor) continue;
if (context.Pixels[width * p.Y + p.X] == fillColor) continue;
if (context.Pixels[width * p.Y + p.X].MaxDiff(outlineColor) > maxdiff)
{
context.Pixels[width * p.Y + p.X] = fillColor;
}
else
{
continue;
}
context.Pixels[width * p.Y + p.X] = fillColor;
queue.Add(new Pnt { X = p.X, Y = p.Y - 1 });
queue.Add(new Pnt { X = p.X + 1, Y = p.Y });
queue.Add(new Pnt { X = p.X, Y = p.Y + 1 });
queue.Add(new Pnt { X = p.X - 1, Y = p.Y });
}
target.Invalidate();
}
}
这是Ereaser工具WriteableBitmapEx
public static void FillEllipseCenteredTrsnceparent(this WriteableBitmap bmp, int xc, int yc, int xr, int yr, Color color)
{
using (BitmapContext context = bmp.GetBitmapContext())
{
Func<Color, int> toInt32 = c =>
{
var i = ((((c.A << 0x18) | (((c.R * c.A + 1) >> 8) << 0x10)) | (((c.G * c.A + 1) >> 8) << 8)) | ((c.B * c.A + 1) >> 8));
return i;
};
int[] pixels = context.Pixels;
int width = context.Width;
int height = context.Height;
if ((xr >= 1) && (yr >= 1))
{
int num3;
int num4;
int num5;
int num6;
int num7;
int num8;
int num9 = xr;
int num10 = 0;
int num11 = (xr * xr) << 1;
int num12 = (yr * yr) << 1;
int num13 = (yr * yr) * (1 - (xr << 1));
int num14 = xr * xr;
int num15 = 0;
int num16 = num12 * xr;
int num17 = 0;
//int sa = (color >> 0x18) & 0xff;
//int sr = (color >> 0x10) & 0xff;
//int sg = (color >> 8) & 0xff;
//int sb = color & 0xff;
//bool flag = !doAlphaBlend || (sa == 0xff);
while (num16 >= num17)
{
num5 = yc + num10;
num6 = yc - num10;
if (num5 < 0)
{
num5 = 0;
}
if (num5 >= height)
{
num5 = height - 1;
}
if (num6 < 0)
{
num6 = 0;
}
if (num6 >= height)
{
num6 = height - 1;
}
num3 = num5 * width;
num4 = num6 * width;
num8 = xc + num9;
num7 = xc - num9;
if (num8 < 0)
{
num8 = 0;
}
if (num8 >= width)
{
num8 = width - 1;
}
if (num7 < 0)
{
num7 = 0;
}
if (num7 >= width)
{
num7 = width - 1;
}
for (int i = num7; i <= num8; i++)
{
pixels[i + num3] = toInt32(color);
pixels[i + num4] = toInt32(color);
}
num10++;
num17 += num11;
num15 += num14;
num14 += num11;
if ((num13 + (num15 << 1)) > 0)
{
num9--;
num16 -= num12;
num15 += num13;
num13 += num12;
}
}
num9 = 0;
num10 = yr;
num5 = yc + num10;
num6 = yc - num10;
if (num5 < 0)
{
num5 = 0;
}
if (num5 >= height)
{
num5 = height - 1;
}
if (num6 < 0)
{
num6 = 0;
}
if (num6 >= height)
{
num6 = height - 1;
}
num3 = num5 * width;
num4 = num6 * width;
num13 = yr * yr;
num14 = (xr * xr) * (1 - (yr << 1));
num15 = 0;
num16 = 0;
num17 = num11 * yr;
while (num16 <= num17)
{
num8 = xc + num9;
num7 = xc - num9;
if (num8 < 0)
{
num8 = 0;
}
if (num8 >= width)
{
num8 = width - 1;
}
if (num7 < 0)
{
num7 = 0;
}
if (num7 >= width)
{
num7 = width - 1;
}
for (int j = num7; j <= num8; j++)
{
pixels[j + num3] = toInt32(color);
pixels[j + num4] = toInt32(color);
}
num9++;
num16 += num12;
num15 += num13;
num13 += num12;
if ((num14 + (num15 << 1)) > 0)
{
num10--;
num5 = yc + num10;
num6 = yc - num10;
if (num5 < 0)
{
num5 = 0;
}
if (num5 >= height)
{
num5 = height - 1;
}
if (num6 < 0)
{
num6 = 0;
}
if (num6 >= height)
{
num6 = height - 1;
}
num3 = num5 * width;
num4 = num6 * width;
num17 -= num11;
num15 += num14;
num14 += num11;
}
}
}
}
}
有没有办法将此代码转换为win2dor Sharpdx？