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我尝试在我的树结构中扩展多个列表。

假设我有以下课程。我有 Product 类，其中包含一个包含其子项的列表。这是我的实际树结构。

    class Product
{
    int prodID;
    string prodName;

    List<Product> prodChildren;
    List<Article> articleList;

    //maybe further list...

    public int ProdID
    {
        get { return prodID;}
        set{prodID = value;}
    }

    public string ProdName
    {
        get { return prodName;}
        set {prodName = value;}
    }

    public Product(int id, string name)
    {
        ProdID = id;
        ProdName = name;

        prodChildren = new List<Product>();
        articleList = new List<Article>();
    }

    //...
    //addProdChildren
    //...
    //addArticles
}

 class SalesArticle
{
    int articleNumber;
    string articleName;

    public int ArticleNumber
    {
        get
        {
            return articleNumber;
        }

        set
        {
            articleNumber = value;
        }
    }

    public string ArticleName
    {
        get
        {
            return articleName;
        }

        set
        {
            articleName = value;
        }
    }

    public SalesArticle(int no, string name)
    {
        ArticleNumber = no;
        ArticleName = name;
    }
}

到目前为止，这部分效果很好，但是如何在同一棵树中展开文章列表？我无法让这部分工作。

应该看起来像：

[product1]
---------[product2]
---------[product3]
--------------[article1]
--------------[article2]
--------------[article3]
--------------[article4]
---------[product4]
--------------[product5]
----------------------[articleX]
----------------------[articleX]
----------------------[articleX]
----------------------[articleX]

我的 CanExpandGetter 和 ChildrenGetter 目前非常基础

            tlvProduktStruktur.CanExpandGetter = delegate (object x) { return (x is Product); };

        tlvProduktStruktur.ChildrenGetter = delegate (object x) 
        {
            if (((Product)x).ProduktChildren.Count > 0)
                return ((Product)x).prodChildren;
            else
                return null;

        };

更新

--------------------------------------

如果有人感兴趣，我找到了解决方案：

我的产品类有一个对象列表：

    class Product
{
    int prodID;
    string prodName;

    List<object> childItems;

    ...
}

现在我可以将每种类型的对象或其他列表添加到此对象列表中，例如：

            Product rootProduct = new Product(1, "root");

        Article artikel1 = new Article();
        Article artikel2 = new Article();

        //this root product has a working process which contains a list of articles
        WorkingProcess wp = new WorkingProcess();
        wp.add(artikel1);
        wp.add(artikel2);

        childItems.Add(wp);

        //let's assume the root product has also two children
        Product p1 = new Product(2, "sub product 1");
        Product p2 = new Product(3, "sub product 2");

        rootProduct.childItems.Add(p1);
        rootProduct.childItems.Add(p2);

结构如下所示：

根产品
-  -  - 工作流程
-  -  -  -  - -第1条
------------第2条
------子产品1
------子产品2

现在我们只需要更改 CanExpandGetter 和 ChildrenGetter：

            // when the node can be expanded

tlvProduktStruktur.CanExpandGetter = 委托（对象 x）{

            //if the product has child items (working process and/or child products) show it as expandable
            if (x is Product)
                if (((Product)x).ChildItems.Count > 0)
                    return true;

            //if the working process has articles, show it as expandable
            if (x is WorkingProcess)
                if (((WorkingProcess)x).ArticleList.Count > 0)
                    return true;

            return false;

        };


        tlvProduktStruktur.ChildrenGetter = delegate (object x) {

//check the type and expand its children

            //show the child items (working process and/or child products) of the current product
            if (x is Product)
                if (((Product)x).ChildItems.Count > 0)
                {
                    return ((Product)x).ChildItems;
                }

            //show the articles of the working process
            if (x is WorkingProcess)
                if (((WorkingProcess)x).ArticleList.Count > 0)
                    return ((WorkingProcess)x).ArticleList;

            return new List<object>();

        };

现在你应该得到预期的结果。

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