如何从 mule 中的 catch-exception-strategy 重新抛出异常。
尝试使用以下流程并在“flowdemo”错误处理出现异常后,它不会进入 mdemoflow 的错误处理。它执行位于 flow-ref 之后的记录器。
<mule ....>
<sub-flow name="exceFlow">
<logger level="ERROR" doc:name="Logger"/>
<expression-component doc:name="Expression"><![CDATA[throw new java.lang.IllegalArgumentException('bad arg');]]></expression-component>
<validation:is-true expression="false" doc:name="Validation"/>
<scripting:component doc:name="Script">
<scripting:script engine="Groovy"><![CDATA[throw new java.lang.IllegalArgumentException('bad arg')]]></scripting:script>
</scripting:component>
<logger level="INFO" doc:name="Logger"/>
</sub-flow>
<flow name="flowdemo" processingStrategy="synchronous">
<expression-component doc:name="Expression"><![CDATA[flowVars.dummy = flowVars.fake.test]]></expression-component>
<catch-exception-strategy doc:name="Catch Exception Strategy" >
<flow-ref name="exceFlow" doc:name="Flow Reference"/>
</catch-exception-strategy>
</flow>
<flow name="mdemoFlow" processingStrategy="synchronous">
<poll doc:name="Poll">
<fixed-frequency-scheduler frequency="3" timeUnit="MINUTES"/>
<logger level="INFO" doc:name="Logger"/>
</poll>
<flow-ref name="flowdemo" doc:name="flowdemo"/>
<logger level="INFO" doc:name="Logger"/>
<catch-exception-strategy doc:name="Catch Exception Strategy">
<logger message="test logging in error" level="ERROR" doc:name="Logger"/>
<logger level="INFO" doc:name="Logger"/>
</catch-exception-strategy>
</flow>
</mule>