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基于这个答案https://stackoverflow.com/a/2111420/3989524我首先创建了一个工作 SQL:

SELECT d.*
FROM device d
LEFT OUTER JOIN installation_record ir1 ON (d.id = ir1.device)
LEFT OUTER JOIN installation_record ir2 ON (d.id = ir2.device AND ir1.install_date < ir2.install_date)
WHERE ir2.id IS NULL AND ir1.uninstall_date IS NULL;

然后是一个条件查询,它看起来会产生一个等效的 HQL(最后),但是 Hibernate 会抛出一个错误:

org.hibernate.hql.internal.ast.QuerySyntaxException:with-clause 引用了两个不同的 from-clause 元素

错误消息中的 HQL:

SELECT generatedAlias0 FROM Device AS generatedAlias0 
LEFT JOIN generatedAlias0.installationRecordList AS generatedAlias1 
LEFT JOIN generatedAlias0.installationRecordList AS generatedAlias2 
WITH generatedAlias1.installDate<generatedAlias2.installDate 
WHERE ( generatedAlias2.id IS NULL ) AND ( generatedAlias1.uninstallDate IS NULL )

条件查询:

final CriteriaBuilder cb = em.getCriteriaBuilder();
final CriteriaQuery<Device> cq = cb.createQuery(Device.class);
final Root<Device> root = cq.from(Device.class);
final Join<Device, InstallationRecord> join1 = root.join(Device_.installationRecordList, JoinType.LEFT);
final Join<Device, InstallationRecord> join2 = root.join(Device_.installationRecordList, JoinType.LEFT);

join2.on(cb.lessThan(join1.get(InstallationRecord_.installDate), join2.get(InstallationRecord_.installDate)));
cq.select(root);

final List<Predicate> predicates = Lists.newArrayList();
predicates.add(cb.isNull(join2.get(InstallationRecord_.id)));
predicates.add(cb.isNull(join1.get(InstallationRecord_.uninstallDate)));
cq.where(predicates.toArray(new Predicate[] {}));

return em.createQuery(cq).getResultList();

反正有没有得到我想要的东西,或者没有其他方法可以解决一些内部休眠错误。

4

1 回答 1

-1

也许:

final Join<InstallationRecord, InstallationRecord> join2 = root.join(InstallationRecord_.id, JoinType.LEFT);

因为ON (d.id = ir2.device AND在 HQL 中缺少。

于 2016-09-02T17:30:49.203 回答