algorithm - 计算标签云中标签的字体大小的公式是什么？

Question

我有一个标签云，我需要知道如何更改最常用标签的字体大小。

我需要设置最小字体大小和最大字体大小。

Answer 1

您可以对与某个标签相关联的项目数量（相对于最大标签）进行线性或对数评估，将其乘以最小和最大字体大小之间的差异，然后将其添加到最小字体大小。例如，伪代码中的数学可能是：

let min = 12, max = 24
for each tag
    font = (items / items in biggest tag) * (max - min) + min

Answer 2

为了使@Delan 的答案更清楚，我用我熟悉的语言创建了一些示例。

Javascript 中的示例

var tags =
[
    { Name: "c#", Uses: 100 },
    { Name: ".net", Uses: 75 },
    { Name: "typescript", Uses: 50 },
    { Name: "lua", Uses: 50 },
    { Name: "javascript", Uses: 25 },
    { Name: "jquery", Uses: 1 },
    { Name: "c++", Uses: 0 },
];

var max = 100; // Should be computed
var min = 0;   // Should be computed

var fontMin = 10;
var fontMax = 20;

for (var i in tags)
{
    var tag = tags[i];

    var size = tag.Uses == min ? fontMin
        : (tag.Uses / max) * (fontMax - fontMin) + fontMin;
}

C# 中的示例

var tags = new List<Tag>
{
    new Tag { Name = "c#", Uses = 100 },
    new Tag { Name = ".net", Uses = 75 },
    new Tag { Name = "typescript", Uses = 50 },
    new Tag { Name = "lua", Uses = 50 },
    new Tag { Name = "javascript", Uses = 25 },
    new Tag { Name = "jquery", Uses = 5 },
    new Tag { Name = "c++", Uses = 5 },
};

int max = tags.Max(o => o.Uses);
int min = tags.Min(o => o.Uses);

double fontMax = 20;
double fontMin = 10;

foreach (var tag in tags)
{
    double size = tag.Uses == min ? fontMin
        : (tag.Uses / (double)max) * (fontMax - fontMin) + fontMin;
}

Answer 3

Try:

<div data-i2="fontSize:[10,30]">
    <span data-i2="rate:1">A</span>
    <span data-i2="rate:4">B</span>
    <span data-i2="rate:7">C</span>
    <span data-i2="rate:12">G</span>
    <span data-i2="rate:5">H</span>
</div>

Then

i2.emph();

http://jsfiddle.net/EUaC5/1/

Answer 4

在这里你可以检查它是如何在 WordPress 中完成的：

https://github.com/WordPress/WordPress/blob/26bda18a23174afb048afbe62296c76a62add542/wp-includes/category-template.php#L955

fontStep = (maxSize - minSize) / (maxCount - minCount);
fontSize = smallestFont + ( tagCount - minCount ) * fontStep;

Answer 5

我想出了这个：

max_word_count = 412  # should count from list
min_word_count = 44   # should count from list
difference = max_word_count - min_word_count
min_weight = 99 / difference * min_word_count

for each tag
    weight = 99 / difference * this_word_count - min_weight + 1

这给了我 1 到 100 之间的加权词。它在znaci.net/arhiv对我来说非常有效。

免责声明：我不擅长数学。