0

请帮助..我无法弄清楚这个奇怪的问题。我的应用程序支持 iAds 和多任务处理。该应用程序可以部署到 iphone 上并且运行良好,但是当我尝试在 iphone 3g(使用 iOS 3.1.2)上部署我的应用程序时,它会在控制台上引发以下错误。我尝试注释掉 iAds 的代码,但不确定这里发生了什么..请帮助大家..谢谢

[Session started at 2010-08-31 13:01:05 -0500.]
GNU gdb 6.3.50-20050815 (Apple version gdb-1470) (Thu May 27 05:54:06 UTC 2010)
Copyright 2004 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB.  Type "show warranty" for details.
This GDB was configured as "--host=i386-apple-darwin --target=arm-apple-darwin".tty /dev/ttys003
Loading program into debugger…
warning: Unable to read symbols from "iAd" (not yet mapped into memory).
Program loaded.
target remote-mobile /tmp/.XcodeGDBRemote-32678-64
Switching to remote-macosx protocol
mem 0x1000 0x3fffffff cache
mem 0x40000000 0xffffffff none
mem 0x00000000 0x0fff none
run
Running…
[Switching to thread 11779]
[Switching to thread 11779]
sharedlibrary apply-load-rules all
continue
2010-08-31 13:02:14.666 SugarCRMReleaseOne[5256:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSURL initWithString:relativeToURL:]: nil string parameter'
2010-08-31 13:02:14.709 SugarCRMReleaseOne[5256:207] Stack: (
    853417245,
    845594132,
    852966195,
    852966099,
    871903965,
    871903579,
    871903537,
    211149,
    211529,
    147487,
    171893,
    290105,
    279933,
    853174415,
    818198404,
    818198252,
    818198196,
    818197260,
    818200460,
    818194688,
    818192276,
    818173840,
    818172052,
    834382224,
    853165355,
    853163039,
    834376564,
    817839152,
    817832496,
    8857,
    8720
)
terminate called after throwing an instance of 'NSException'
Program received signal:  “SIGABRT”.
kill
quit

编辑

1 [syncDelegateImpl loginHandler];

2 -(void) loginHandler { SCRMsugarsoap* 服务 = [[SCRMsugarsoap alloc] initWithUrl:serverURL]; service.logging = 是的;服务.用户名 = 用户名;service.password = 密码;[服务登录:自我操作:@selector(sessionIdHandler:) user_auth: [[[SCRMuser_auth alloc] initWithUsername:userName andPassword:password]autorelease] application_name:@""]; 【服务发布】;}

3 当遇到[service login:self action:@selector(sessionIdHandler:) user_auth: [[[SCRMuser_auth alloc] initWithUsername:userName andPassword:password]autorelease] application_name:@""];

  • (id) initWithUsername: (NSString*) username andPassword: (NSString*) pass { if(self = [super init]) { Soap *converter = [[Soap alloc] init]; SCRMsugarsoap *service = [[SCRMsugarsoap alloc] init];

        [service get_server_version:self action:@selector(get_server_versionHandler:)];
    
        self.user_name = username;
        self.password = [converter tomd5:pass];
    
        [converter release];
        [service release];
    }
    return self;
    

    }

4 现在遇到 [service get_server_version:self action:@selector(get_server_versionHandler:)]; 在上述方法中..

  • (SoapRequest*) get_server_version: (id) _target action: (SEL) _action { NSMutableArray* _params = [NSMutableArray array];

    NSString* _envelope = [Soap createEnvelope: @"get_server_version" forNamespace: self.namespace withParameters: _params withHeaders: self.headers];
    SoapRequest* _request = [SoapRequest create: _target action: _action service: self soapAction: (@"%@/get_server_version", serverURL) postData: _envelope deserializeTo: @"NSString"];
    [_request send];
    return _request;
    

    }

    5 现在它尝试调用 SOAP Request 类方法

    • (SoapRequest*) create: (SoapHandler*) handler action: (SEL) action service: (SoapService*) service soapAction: (NSString*) soapAction postData: (NSString*) postData deserializeTo: (id) deserializeTo { SoapRequest* request = [ SoapRequest create: handler action: action urlString: service.serviceUrl soapAction: soapAction postData:postData deserializeTo:deserializeTo]; request.defaultHandler = service.defaultHandler; request.logging = service.logging; request.username = service.username; request.password = service.password; 退货请求;}

6 因此,当它尝试设置请求时,将调用以下方法

+ (SoapRequest*) create: (SoapHandler*) handler action: (SEL) action urlString: (NSString*) urlString soapAction: (NSString*) soapAction postData: (NSString*) postData deserializeTo: (id) deserializeTo {
    SoapRequest* request = [[SoapRequest alloc] init];
    //request.url = nil;
    //if(urlString!=nil)
    //{
    request.url=[NSURL URLWithString: urlString];
    //}
    request.soapAction = soapAction;
    request.postData = [postData retain];
    request.handler = handler;
    request.deserializeTo = deserializeTo;
    request.action = action;
    request.defaultHandler = nil;
    return [request autorelease];
}

在设置 url 时它会抛出 objc_exception_throw ..它在 iphone 4 上运行良好,但是当我尝试在 iphone 3 上部署时它会抛出错误..

我的应用程序中有多任务处理和 iAd 框架,我通过以下方式检查版本:

if ([[UIDevice currentDevice].systemVersion floatValue] >=3.2)
{
do iphone 4 stuff
}
else
{
do iphone 3 stuff
}
4

1 回答 1

0

Your issue is right there in the report: you're passing nil to initWithString: which causes the exception. Either check for nil before calling the initializer or ensure the string value another way to fix the problem.

Edit: I'd recommend simplifying your class initializer, but that's not your problem. If urlString isn't properly formed, the URL will return nil. According to Apple's docs: The string with which to initialize the NSURL object. Must conform to RFC 2396. This method parses URLString according to RFCs 1738 and 1808.

That may be your problem, though I don't know if you posted enough code to be sure.

于 2010-08-31T18:41:26.923 回答