我有一个NSObject用于存储/保存对象属性的对象，其中一个是“名称”属性转换为NSString. 我还使用以下方法从 SQLite DB 中为所述对象提取数据：
- (void) getDataToDisplay:(NSString *)dbPath {
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) {
NSString *queryOnStyle = [NSString stringWithFormat:
@"SELECT WineId, Name FROM wine WHERE StyleId = %d", dataManager.styleId];
const char *sql = [queryOnStyle UTF8String];
sqlite3_stmt *selectstmt;
if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) {
while(sqlite3_step(selectstmt) == SQLITE_ROW) {
Wine *w = [[Wine alloc] init];
w.wineId = sqlite3_column_int(selectstmt, 0);
w.wineName = [NSString stringWithUTF8String:
(char *)sqlite3_column_text(selectstmt, 1)];
[dataManager.wines addObject:w];
[w release];
}
}
}
else
sqlite3_close(database); //Even though the open call failed, close the database connection to release all the memory.
}
酒是我的对象。如果我此时登录w.wineName，没有问题。当我尝试dataManager.wines在自定义 tableView 中从数组中访问对象的属性时，稍后会出现问题。它突然把我wineName当作一个UIImageView而不是一个NSString......
我一生都无法追溯到曾经被铸造为 a 的任何事情，UIImageView也不知道为什么它会设置该属性。这是我的自定义 tableView 的代码：
#pragma mark -
#pragma mark HorizontalTableViewDelegate methods
- (NSInteger)numberOfColumnsForTableView:(HorizontalTableView *)tableView {
return [dataManager.wines count];
}
- (UIView *)tableView:(HorizontalTableView *)aTableView viewForIndex:(NSInteger)index {
UIView *vw = [aTableView dequeueColumnView];
if (!vw) {
[[NSBundle mainBundle] loadNibNamed:@"ColumnView" owner:self options:nil];
vw = self.columnView;
self.columnView = nil;
}
// Get the wineId from the array of wineId integers
Wine *w = [dataManager.wines objectAtIndex:index];
int tempWineId = w.wineId;
NSString *tempWineName = [NSString stringWithFormat:@"%@", w.wineName];
NSLog(@"%@", tempWineName); \\RETURNS TEMPWINENAME AS A UIIMAGEVIEW
[w release];
return vw;
}
- (CGFloat)columnWidthForTableView:(HorizontalTableView *)tableView {
//TODO: This value needs to change if changed in IB
return 209.0f;
}
有任何想法吗？