4

如何在 Objective-C 中反转 NSArray 的内容?

假设我有一个包含这些数据的数组

NSArray arrayObj = [[NSArray alloc]init];
arrayObj atindex 0 holds this: "1972"
arrayObj atindex 1 holds this: "2005"
arrayObj atindex 2 holds this: "2006"
arrayObj atindex 3 holds this: "2007"

Now i want to inverse the order of array like this:

arrayObj atindex 0 holds this: "2007"
arrayObj atindex 1 holds this: "2006"
arrayObj atindex 2 holds this: "2005"
arrayObj atindex 3 holds this: "1972"

怎么达到这个??

谢谢你。

4

3 回答 3

30
NSArray* reversed = [[originalArray reverseObjectEnumerator] allObjects];
于 2010-08-27T13:07:21.953 回答
4

以相反的顺序迭代您的数组并在这样做的同时创建一个新数组:

NSArray *originalArray = [NSArray arrayWithObjects:@"1997", @"2005", @"2006", @"2007",nil];

NSMutableArray *newArray = [[NSMutableArray alloc] initWithObjects:nil];

for (int i = [originalArray count]-1; i>=0; --i)
{
    [newArray addObject:[originalArray objectAtIndex:i]];
}
于 2010-08-27T12:46:30.583 回答
0

Or the Scala-way:

-(NSArray *)reverse
{
    if ( self.count < 2 )
        return self;
    else
        return [[self.tail reverse] concat:[NSArray arrayWithObject:self.head]];
}

-(id)head
{
    return self.firstObject;
}

-(NSArray *)tail
{
    if ( self.count > 1 )
        return [self subarrayWithRange:NSMakeRange(1, self.count - 1)];
    else
        return @[];
}
于 2015-01-23T08:37:07.327 回答