我正在 Unity 中为 iPhone 开发一个 AR 应用程序,它从网络服务器下载资产包并将它们附加到图像目标。到目前为止,几乎一切正常——除了当应用程序尝试加载资产包时,我收到以下错误:
'asset/bundle/url' 无法加载,因为它不是使用正确的版本或构建目标构建的。
我使用以下脚本创建了资产包,对 Unity 文档稍作修改:
using UnityEditor;
public class CreateAssetBundles
{
[MenuItem ("Assets/Build AssetBundles")]
static void BuildAllAssetBundles ()
{
BuildPipeline.BuildAssetBundles ("Assets/AssetBundles", BuildAssetBundleOptions.None, BuildTarget.iOS);
}
}
然后我使用 scp 将资产包上传到服务器。该应用程序可以很好地下载资产包,但无法加载它们。这是代码:
IEnumerator DownloadAndCache (string username, string modelName){
// Wait for the Caching system to be ready
while (!Caching.ready) {
Debug.Log ("Waiting on caching");
yield return null;
}
//Compute request url for server
UriBuilder uriBuilder = new UriBuilder();
uriBuilder.Scheme = "http";
uriBuilder.Host = BaseURL;
uriBuilder.Path = username.Trim() + "/" + modelName.Trim();
string BundleURL = uriBuilder.ToString ();
Debug.Log ("Attempting to download " + BundleURL);
// Load the AssetBundle file from Cache if it exists with the same version or download and store it in the cache
using(WWW www = WWW.LoadFromCacheOrDownload (BundleURL, version)){
yield return www;
if (www.error != null) {
Debug.Log ("Download error");
throw new Exception ("WWW download had an error:" + www.error);
}
AssetBundle bundle = www.assetBundle;
Debug.Log ("Got assets "+string.Join(",", bundle.GetAllAssetNames ()));
GameObject loadedModel = Instantiate(bundle.LoadAllAssets()[0]) as GameObject;
//attach to the image target
loadedModel.transform.parent = ImageTargetTemplate.gameObject.transform;
loadedModel.transform.position = new Vector3 (0, 0, 0);
loadedModel.transform.localScale = new Vector3 (1, 1, 1);
// Unload the AssetBundles compressed contents to conserve memory
bundle.Unload(false);
} // memory is freed from the web stream (www.Dispose() gets called implicitly)
}
到目前为止,我已经尝试过:
- 设置构建目标 BuildTarget.iPhone - 没有区别
- 使用 Unity 中的资产包管理器 API 构建资产包
- 在 iOS 的构建选项中取消选中“剥离引擎代码” - 我在另一个论坛上听说这可能会导致问题。
任何帮助表示赞赏。
-更新- 我根据程序员的建议修改了BuildAssetBundle
脚本,并在播放器设置面板中将目标平台从“iPhone”切换到“通用”。我很确定这就是解决问题的方法。