11

我为两种不同的传感器开发了应用程序。它们分别工作正常，但是当我尝试将它们一起使用并创建两个不同的总线时，Alljoyn 给出了这个例外。

org.alljoyn.services.common.BusAlreadyExistException：该对象先前已使用 BusAttachment 设置。

下面是我的连接源代码。谁能告诉我为什么我会遇到这个问题。

private void connect() 
        {           org.alljoyn.bus.alljoyn.DaemonInit.PrepareDaemon(getApplicationContext());

            bus = new BusAttachment("ControlPanelBrowser", BusAttachment.RemoteMessage.Receive);
            bus.registerBusListener(new BusListener());


            Status status = bus.registerBusObject(mControlPanelSignalInterface, Constants.SERVICE_PATH);


            if (status != Status.OK) {

                Log.d(TAG, "Problem while registering bus object");

            }   

            SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
            srpPassword = settings.getString(PREFS_PASSWORD, DEFAULT_SECURED_SRP_PASSWORD);

            SrpAnonymousKeyListener authListener = new SrpAnonymousKeyListener(this, logger, AUTH_MECHANISMS);
            Status authStatus = bus.registerAuthListener(authListener.getAuthMechanismsAsString(), 
                    authListener, getKeyStoreFileName());

            if ( authStatus != Status.OK ) {
                Log.e(TAG, "Failed to register AuthListener");
            }

            status = bus.connect();


            if (Status.OK == status){

                String daemonName = Constants.DAEMON_NAME_PREFIX + ".ControlPanelBrowser.G" + 
                        bus.getGlobalGUIDString();

                int flag = BusAttachment.ALLJOYN_REQUESTNAME_FLAG_DO_NOT_QUEUE;

                Status reqStatus = bus.requestName(daemonName, flag);

                if (reqStatus == Status.OK) {

                    Status adStatus = bus.advertiseName(Constants.DAEMON_QUIET_PREFIX +
                            daemonName, SessionOpts.TRANSPORT_ANY);

                    if (adStatus != Status.OK){
                        bus.releaseName(daemonName);
                        Log.e(TAG, "Failed to advertise daemon name: '" + daemonName + "', Error: '" + status + "'");
                    }
                    else{
                        Log.d(TAG, "Succefully advertised daemon name: '" + daemonName + "'");
                    }
                }
                else {
                    Log.e(TAG, "Failed to request daemon name: '" + daemonName + "', Error: '" + status + "'");
                }
            }


            status = bus.registerSignalHandlers(mControlPanelSignalInterface);

            if (status != Status.OK) {
                Log.d(TAG, "Problem while registering signal handlers");
            }

            // Initialize AboutService

            aboutClient = AboutServiceImpl.getInstance();
            aboutClient.setLogger(logger);
            try {
                aboutClient.startAboutClient(bus);

                for (String iface :  ANNOUNCE_IFACES) {


                    aboutClient.addAnnouncementHandler(this, new String[] {iface});

                }
            } catch (Exception e) {

                logger.error(TAG, "Unable to start AboutService, Error: " + e.getMessage());

            }


        }
4

2 回答 2

1

使用registerBusObject双胞胎，然后你可以制作一个信号总线附件

于 2016-03-08T05:09:55.573 回答
0

为什么不创建两个接口，一个接口分别用于一个传感器。然后将这两个接口添加到实现这两个接口和busObject的类中，并将该类的实现注册为BusObject。

例如

Sensor1_interface.java and Sensor2_interface.java //are my two interface classes

创建一个新的类 Sensor_InterfaceList，它实现了两个接口和 BusObject

class Sensor_InterfaceList implements Sensor1_interface,Sensor2_interface,BusObject
   {
    // implment your interfaces here
    .....
    }
private Sensor_InterfaceList mySensor_InterfaceList;
mySensor_InterfaceList = new Sensor_InterfaceList();
myBus.registerBusObject(mySensor_InterfaceList,"/your/path");

这应该可以解决您的问题:)

于 2016-03-09T16:02:56.710 回答