1

好的，那么我如何制作我的代码，而不是把 1 到 4 我可以只输入一个关键字，如“冻结”或“冻结”我怎么能在我的代码中放置一个关键字搜索器，非常感谢所有帮助，谢谢你在高级:)

    def menu():
  print("Welcome to Kierans Phone Troubleshooting program")
  print("Please Enter your name")
  name=input()
  print("Thanks for using Kierans Phone Troubleshooting program "+name +"\n")

def start():
  select = " "
  print("Would you like to start this program? Please enter either y for yes or n for no")
  select=input()
  if select=="y":
    troubleshooter()
  elif select=="n":
    quit
  else:
    print("Invalid please enter again")

def troubleshooter():
  print("""Please choose the problem you are having with your phone (input 1-4):
1) My phone doesn't turn on
2) My phone is freezing
3) The screen is cracked
4) I dropped my phone in water\n""")
  problemselect = int(input())
  if problemselect ==1:
    not_on()
  elif problemselect ==2:
    freezing()
  elif problemselect ==3:
    cracked()
  elif problemselect ==4:
    water()
  start()

def not_on():
  print("Have you plugged in the charger?")
  answer = input()
  if answer =="y":
    print("Charge it with a diffrent charger in a diffrent phone socket. Does it work?")
  else:
    print("Plug it in and leave it for 20 mins, has it come on?")
  answer = input()
  if answer=="y":
    print("Are there any more problems?")
  else:
    print("Restart the troubleshooter or take phone to a specialist\n")
  answer=input()
  if answer =="y":
    print("Restart this program")
  else:
    print("Thank you for using my troubleshooting program!\n")

def freezing():
  print("Charge it with a diffrent charger in a diffrent phone socket")
  answer = input("Are there any more problems?")
  if answer=="y":
    print("Restart the troubleshooter or take phone to a specialist\n")
  else:
    print("Restart this program\n")

def cracked():
  answer =input("Is your device responsive to touch?")
  if answer=="y":
    answer2 = input("Are there any more problems?")
  else:
    print("Take your phone to get the screen replaced")
  if answer2=="y":
    print("Restart the program or take phone to a specialist\n")
  else:
    print("Thank you for using my troubleshooting program!\n")

def water():
  print("Do not charge it and take it to the nearest specialist\n")

menu()
while True:
  start()
  troubleshooter()
4

2 回答 2

1

您正在寻找一个enum

from enum import Enum
class Status(Enum):
    NOT_ON = 1
    FREEZING = 2
    CRACKED = 3
    WATER = 4

然后在您的if检查中，您执行以下操作：

if problemselect == Status.NOT_ON:
    ...
elif problemselect == Status.FREEZING:
    ...
于 2016-02-16T18:29:14.170 回答
1

由于您希望用户输入电话问题的描述，因此您可能需要一个问题列表以及与这些问题相关的关键字。下面的程序展示了如何安排这样的数据库以及如何根据用户的输入来搜索它。这个解决方案有更快的替代方案（例如索引数据库），但这个基本实现暂时应该足够了。您将需要提供有关如何解决问题的更多代码和信息，但对您之前的问题的回答应该有助于您在这方面指导您。

#! /usr/bin/env python3

# The following is a database of problem and keywords for those problems.
# Its format should be extended to take into account possible solutions.
PROBLEMS = (('My phone does not turn on.',
             {'power', 'turn', 'on', 'off'}),
            ('My phone is freezing.',
             {'freeze', 'freezing'}),
            ('The screen is cracked.',
             {'cracked', 'crack', 'broke', 'broken', 'screen'}),
            ('I dropped my phone in water.',
             {'water', 'drop', 'dropped'}))


# These are possible answers accepted for yes/no style questions.
POSITIVE = tuple(map(str.casefold, ('yes', 'true', '1')))
NEGATIVE = tuple(map(str.casefold, ('no', 'false', '0')))


def main():
    """Find out what problem is being experienced and provide a solution."""
    description = input('Please describe the problem with your phone: ')
    words = {''.join(filter(str.isalpha, word))
             for word in description.lower().split()}
    for problem, keywords in PROBLEMS:
        if words & keywords:
            print('This may be what you are experiencing:')
            print(problem)
            if get_response('Does this match your problem? '):
                print('The solution to your problem is ...')
                # Provide code that shows how to fix the problem.
                break
    else:
        print('Sorry, but I cannot help you.')


def get_response(query):
    """Ask the user yes/no style questions and return the results."""
    while True:
        answer = input(query).casefold()
        if answer:
            if any(option.startswith(answer) for option in POSITIVE):
                return True
            if any(option.startswith(answer) for option in NEGATIVE):
                return False
        print('Please provide a positive or negative answer.')


if __name__ == '__main__':
    main()
于 2016-02-17T16:59:36.390 回答