1

好的，所以我在编程作业上遇到了很多麻烦。我们将从文本文件中读取信息并使用我们创建的某些方法对其进行格式化。我能够很好地从文本文件的第一行读取信息，但之后我得到一个错误。我的代码如下：

String name1 = scan.nextLine();
    String name2 = scan.nextLine();
    scan.close();
    int length = name1.length();
    int count = 0;
    int a = 0;
    int b = 1;
    while(end != true)
    {

        String check = name1.substring(a,b);
        a++;
        b++;
        count++;
        char z = check.charAt(0);
        if(z == '0' || z == '1' || z == '2' || z == '3' || z == '4' || z == '5' || z == '6' || z == '7' || z == '8' || z == '9')
        {
            end = true;

        }
        if(count == length)
        {
            end = true;

        }
    }
    String number1 = name1.substring(count,length);
    int number01 = Integer.parseInt(number1);
    name1=name1.substring(0, count-1);
    int d = name1.indexOf(" ");
    int length1 = name1.length();
    String name1first = name1.substring(0,d);
    name1first = name1first.trim();
    String name1last = name1.substring(d,length1);
    name1last = name1last.trim();

    System.out.println(name1first);
    System.out.println(name1last);
    System.out.println(number01);


    length = name2.length();
   int  countt = 0;
int  aa = 0;
int  bb = 1;
    while(end != true)
    {

        String check = name2.substring(aa,bb);
        aa++;
        bb++;
        countt++;
        char z = check.charAt(0);
        if(z == '0' || z == '1' || z == '2' || z == '3' || z == '4' || z == '5' || z == '6' || z == '7' || z == '8' || z == '9')
        {
            end = true;

        }
        if(countt == length)
        {
            end = true;

        }
    }
    String number2 = name2.substring(countt,length);
    int number02 = Integer.parseInt(number2);
    name2=name2.substring(0, countt-1);
    d = name2.indexOf(" ");
    int length2 = name2.length();
    String name2first = name2.substring(0,d);
    name2first = name2first.trim();
    String name2last = name2.substring(d,length2);
    name2last = name2last.trim();

    System.out.println(name2first);
    System.out.println(name2last);
    System.out.println(number02);

我得到这个错误：

Exception in thread "main" java.lang.NumberFormatException: For input string: "Jennifer Sutter 52114"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at Salary.main(Salary.java:101)
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1 回答 1

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这很明显为什么你会得到这个例外：

您正在尝试将“Jennifer Sutter 52114”转换为整数。

try{}catch()解决方案是在尝试调用时首先使用块Integer.parseInt()。

我认为您正在尝试获取最后一位字符串并将其转换为整数：并且由于您正在使用它，因此Scanner您可以nextInt()像这样：

new Scanner(theStringWhichMightHaveANumber).nextInt();

于 2012-11-05T04:01:25.103 回答