我正在尝试在我的相机应用程序中为白平衡和温度颜色设置自定义值。我正在使用 camera2 API,我正在尝试不同的方法来设置这个值。我从 excel 文件中找到了一种方法,可以从 100 到 100.000 之间的白平衡值中获取正确的 RGB 温度矩阵 [红、绿、蓝]。
我将此方法附加到 Seekbar 并且它工作正常,当我尝试聚焦白色时出现我的问题,然后它变成粉红色。任何一种光在屏幕上看起来都像是一个粉红色的手电筒。
我以这种方式设置值:
mPreviewRequestBuilder.set(CaptureRequest.COLOR_CORRECTION_MODE, CaptureRequest.COLOR_CORRECTION_MODE_TRANSFORM_MATRIX);
RggbChannelVector rggb = getTemperatureVector(seekBackSelectedTemperature);
mPreviewRequestBuilder.set(CaptureRequest.COLOR_CORRECTION_GAINS, myRggbChannelVector);
换句话说,我获取矩阵的方法是这样的:
public static RggbChannelVector getTemperatureVector (int WhiteBalanceValue){
float InsertTemperature = WhiteBalanceValue;
float temperature = InsertTemperature / 100;
float red;
float green;
float blue;
//Calculate red
if (temperature <= 66)
red = 255;
else {
red = temperature - 60;
red = (float) (329.698727446 * (Math.pow((double) red, -0.1332047592)));
if (red < 0)
red = 0;
if (red > 255)
red = 255;
}
//Calculate green
if (temperature <= 66) {
green = temperature;
green = (float) (99.4708025861 * Math.log(green) - 161.1195681661);
if (green < 0)
green = 0;
if (green > 255)
green = 255;
} else
green = temperature - 60;
green = (float) (288.1221695283 * (Math.pow((double) red, -0.0755148492)));
if (green < 0)
green = 0;
if (green > 255)
green = 255;
//calculate blue
if (temperature >= 66)
blue = 255;
else if (temperature <= 19)
blue = 0;
else {
blue = temperature - 10;
blue = (float) (138.5177312231 * Math.log(blue) - 305.0447927307);
if (blue < 0)
blue = 0;
if (blue > 255)
blue = 255;
}
RggbChannelVector finalTemperatureValue = new RggbChannelVector(red/255,(green/255)/2,(green/255)/2,blue/255);
return finalTemperatureValue;
}
也许是因为我的 CaptureRequest 的方法不正确,但我没有找到修复它的方法。