我相信这对你来说是一个简单的问题。
如何用一个 GKState 编写一个带有两个参数的函数?
更新
苹果使用
func willExitWithNextState(_ nextState: GKState)
如果我使用somefunc(state:GKState)
效果很好
虽然somefunc(state:GKState, string:String)
不起作用,为什么???
其他示例
我试过这个:
class Pippo:GKState {}
//1
func printState (state: GKState?) {
print(state)
}
printState(Pippo) //Error cannot convert value of type '(Pippo).Type' (aka 'Pippo.Type') to expected argument type 'GKState?'
//2
func printStateAny (state: AnyClass?) {
print(state)
}
printStateAny(Pippo) //NO Error
//3
func printStateGeneral <T>(state: T?) {
print(state)
}
printStateGeneral(Pippo) //No Error
//4
func printStateAnyAndString (state: AnyClass?, string:String) {
print(state)
print(string)
}
printStateAnyAndString(Pippo/*ExpectedName Or costructor*/, string: "Hello") //ERROR
printStateAnyAndString(Pippo()/*ExpectedName Or costructor*/, string: "Hello") //ERROR cannot convert value of type 'Pippo' to expected argument type 'AnyClass?'
解决方案感谢@0x141E
func printStateAnyAndString (state: GKState.Type, string:String) {
switch state {
case is Pippo.Type:
print("pippo")
default:
print(string)
}
}
printStateAnyAndString(Pippo.self, string: "Not Pippo")
谢谢您的回复