ios - NSDecimalNumber 如何判断是否有小数部分

Question

我有一个用例，我想确定 Swift 中的 NSDecimalNumber 是否有小数部分（0 除外）。我可以截断小数部分，但这涉及创建一个新的 NSDecimalNumber，如果可能的话，我想避免这种情况。

我在计算属性中执行此操作，因此我希望它尽可能高效。这是目前我的扩展在操场上的样子：

extension NSDecimalNumber {
    func decimalNumberRoundedToDigits(withDecimals: UInt8, roundingMode: NSRoundingMode = NSRoundingMode.RoundPlain) -> NSDecimalNumber
    {
        // round to required decimals
        let disp = decimalNumberByRoundingAccordingToBehavior(NSDecimalNumberHandler(roundingMode: roundingMode, scale: Int16(withDecimals), raiseOnExactness: false, raiseOnOverflow: false, raiseOnUnderflow: false, raiseOnDivideByZero: false));

        return disp;
    }

    //  Convert the least significant byte into a signed 8-bit integer
    // Currently just truncates the fractional portion - I would like
    // to test it instead and only round if there are decimals.
    var safeByteValue: Int8 {
        get {
            let bits = UInt8(decimalNumberRoundedToDigits(0).longLongValue & 0xFF);

            return Int8(bitPattern: bits);
        }
    };
}

// just a test loop for demonstration
for i in 0...256
{
    print(NSDecimalNumber(unsignedInt: UInt32(bitPattern: Int32(i))).safeByteValue);
}

Answer 1

我不知道这会有多有效，但它确实给了你答案：

extension NSDecimalNumber {
    var hasFractionalComponent: Bool {
        return ("\(num)").unicodeScalars.contains(UnicodeScalar("."))
    }
}