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我在我的应用程序图标上添加了 3D Touch 以显示快速操作菜单。我想我应该正确设置它。

问题是，当我在“快速操作”菜单中选择一项时，iPhone 在打开应用程序之前会冻结几秒钟。

这是我的AppDelegate.swift：

import UIKit
import Parse


@available(iOS 9.0, *)
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {

    var window: UIWindow?

    func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
        // Override point for customization after application launch.

        Parse.setApplicationId("xx",
            clientKey: "xx")

        let currentInstallation: PFInstallation = PFInstallation.currentInstallation()
        currentInstallation.badge = 0
        currentInstallation.saveEventually()

        return true
    }

    func applicationWillResignActive(application: UIApplication) {
        // Sent when the application is about to move from active to inactive state. This can occur for certain types of temporary interruptions (such as an incoming phone call or SMS message) or when the user quits the application and it begins the transition to the background state.
        // Use this method to pause ongoing tasks, disable timers, and throttle down OpenGL ES frame rates. Games should use this method to pause the game.
    }

    func applicationDidEnterBackground(application: UIApplication) {
        // Use this method to release shared resources, save user data, invalidate timers, and store enough application state information to restore your application to its current state in case it is terminated later.
        // If your application supports background execution, this method is called instead of applicationWillTerminate: when the user quits.
    }

    func applicationWillEnterForeground(application: UIApplication) {
        // Called as part of the transition from the background to the active state; here you can undo many of the changes made on entering the background.
    }

    func applicationDidBecomeActive(application: UIApplication) {
        // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface.
    }

    func applicationWillTerminate(application: UIApplication) {
        // Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:.
    }

    func application(application: UIApplication, performActionForShortcutItem shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void) {

        let rootNavigationViewController = window!.rootViewController as? UINavigationController
        let rootViewController = rootNavigationViewController?.viewControllers.first as UIViewController?

        rootNavigationViewController?.popToRootViewControllerAnimated(false)

        if shortcutItem.type == "JEGHARALDRI" {
            rootViewController?.performSegueWithIdentifier("JEGHARALDRISEGUE", sender: nil)
        }
        if shortcutItem.type == "PLING" {
            rootViewController?.performSegueWithIdentifier("PLINGSEGUE", sender: nil)
        }
        if shortcutItem.type == "FLASKETUTENPEKERPÅ" {
            rootViewController?.performSegueWithIdentifier("FLASKETUTENPEKERPÅSEGUE", sender: nil)
        }
        if shortcutItem.type == "KORTETTALER" {
            rootViewController?.performSegueWithIdentifier("KORTETTALERSEGUE", sender: nil)
        }
    }
}
4

1 回答 1

1

我认为您的应用程序委托应该更像这样

import UIKit

@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {

    //MARK: - Properties

    var window: UIWindow?

    lazy var quickActionManager: QuickActionsManager = {
        return QuickActionsManager()
    }()

    //MARK: - AppDelegate Methods

    func application(application: UIApplication,
        didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool
    {
        return self.setupQuickActions(launchOptions)
    }

    func application(application: UIApplication, performActionForShortcutItem
        shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void)
    {
        completionHandler(self.quickActionManager.handleShortcut(shortcutItem))
    }

    //MARK: - Private Methods

    private func setupQuickActions(launchOptions: [NSObject: AnyObject]?) -> Bool
    {
        guard let shortcutItem = launchOptions?[UIApplicationLaunchOptionsShortcutItemKey]
        as? UIApplicationShortcutItem else { return false }
        return self.quickActionManager.handleShortcut(shortcutItem)
    }
}

然后你得到所有的逻辑来处理你的快速操作管理器中的快速操作，看起来像这样

//MARK: - Public Methods

    func handleShortcut(shortcut: UIApplicationShortcutItem?) -> Bool
    {
        guard let shortcut = shortcut else { return false }
        // Get the key of the shortcutItem
        let key = self.shortKeyForType(shortcut.type)
        // Check if that key is the key of a knowed viewController
        guard let viewControllerKey = ViewControllerKeys(rawValue: key) else { return false }
        // Try to show This View Controller
        return self.showViewController(viewControllerKey)
    }

假设你有一个 viewController 的枚举来显示匹配每个快速操作。

我希望这能回答您的问题，如果您还有更多问题，请告诉我。

于 2016-01-07T21:12:20.160 回答