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我正在尝试从照片中识别卡片。我设法在理想的照片上做我想做的事,但我现在很难在光线略有不同的情况下应用相同的程序,等等。所以问题是关于使以下轮廓检测更加健壮。

我需要分享我的大部分代码,以便获取者能够制作感兴趣的图像,但我的问题仅与最后一个块和图像有关。

import numpy as np
import cv2
from matplotlib import pyplot as plt
from mpl_toolkits.axes_grid1 import ImageGrid
import math

img = cv2.imread('image.png')
img = cv2.cvtColor(frame, cv2.COLOR_BGR2RGB)
plt.imshow(img)

在此处输入图像描述

然后检测到卡:

# Prepocess
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
blur = cv2.GaussianBlur(gray,(1,1),1000)
flag, thresh = cv2.threshold(blur, 120, 255, cv2.THRESH_BINARY)
# Find contours
contours, hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)
contours = sorted(contours, key=cv2.contourArea,reverse=True) 
# Select long perimeters only
perimeters = [cv2.arcLength(contours[i],True) for i in range(len(contours))]
listindex=[i for i in range(15) if perimeters[i]>perimeters[0]/2]
numcards=len(listindex)
# Show image
imgcont = img.copy()
[cv2.drawContours(imgcont, [contours[i]], 0, (0,255,0), 5) for i in listindex]
plt.imshow(imgcont)

在此处输入图像描述

视角修正:

#plt.rcParams['figure.figsize'] = (3.0, 3.0)
warp = range(numcards)
for i in range(numcards):
    card = contours[i]
    peri = cv2.arcLength(card,True)
    approx = cv2.approxPolyDP(card,0.02*peri,True)
    rect = cv2.minAreaRect(contours[i])
    r = cv2.cv.BoxPoints(rect)

    h = np.array([ [0,0],[399,0],[399,399],[0,399] ],np.float32)
    approx = np.array([item for sublist in approx for item in sublist],np.float32)
    transform = cv2.getPerspectiveTransform(approx,h)
    warp[i] = cv2.warpPerspective(img,transform,(400,400))

# Show perspective correction
fig = plt.figure(1, (10,10))
grid = ImageGrid(fig, 111, # similar to subplot(111)
                nrows_ncols = (4, 4), # creates 2x2 grid of axes
                axes_pad=0.1, # pad between axes in inch.
                aspect=True, # do not force aspect='equal'
                )

for i in range(numcards):
    grid[i].imshow(warp[i]) # The AxesGrid object work as a list of axes.

在此处输入图像描述

那是我遇到了问题。我想检测形状的轮廓。我发现最好的方法是在灰度图像上使用bilateralFilter和的组合:AdaptativeThreshold

fig = plt.figure(1, (10,10))
grid = ImageGrid(fig, 111, # similar to subplot(111)
                nrows_ncols = (4, 4), # creates 2x2 grid of axes
                axes_pad=0.1, # pad between axes in inch.
                aspect=True, # do not force aspect='equal'
                )
for i in range(numcards):
    image2 = cv2.bilateralFilter(warp[i].copy(),10,100,100)
    grey = cv2.cvtColor(image2,cv2.COLOR_BGR2GRAY)
    grey2 = cv2.cv.AdaptiveThreshold(cv2.cv.fromarray(grey), cv2.cv.fromarray(grey), 255, cv2.cv.CV_ADAPTIVE_THRESH_MEAN_C, cv2.cv.CV_THRESH_BINARY, blockSize=31, param1=6)
    grid[i].imshow(grey,cmap=plt.cm.binary) 

在此处输入图像描述

这非常接近我想要的,但是我怎样才能改进它以获得白色的封闭轮廓,而其他一切都是黑色的?

4

2 回答 2

3

为什么不在找到轮廓使用 Canny 并应用透视校正(因为它似乎模糊了边缘)?例如,使用您在问题中提供的小图像(结果可能在更大的图像上更好):

在此处输入图像描述

根据您的代码的某些部分:

import numpy as np
import cv2

import math

img = cv2.imread('image.bmp')

# Prepocess
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
flag, thresh = cv2.threshold(gray, 120, 255, cv2.THRESH_BINARY)

# Find contours
img2, contours, hierarchy = cv2.findContours(thresh, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
contours = sorted(contours, key=cv2.contourArea, reverse=True) 

# Select long perimeters only
perimeters = [cv2.arcLength(contours[i],True) for i in range(len(contours))]
listindex=[i for i in range(15) if perimeters[i]>perimeters[0]/2]
numcards=len(listindex)

card_number = -1 #just so happened that this is the worst case
stencil = np.zeros(img.shape).astype(img.dtype)
cv2.drawContours(stencil, [contours[listindex[card_number]]], 0, (255, 255, 255), cv2.FILLED)
res = cv2.bitwise_and(img, stencil)
cv2.imwrite("out.bmp", res)
canny = cv2.Canny(res, 100, 200)
cv2.imwrite("canny.bmp", canny)

首先,为简单起见,移除除单张卡片之外的所有内容,然后应用 Canny 边缘检测器:

在此处输入图像描述在此处输入图像描述

然后你可以扩张/侵蚀,纠正透视,删除最大的轮廓等。

于 2017-05-15T03:07:42.580 回答
2

除了右下角的图像外,以下步骤通常应该可以工作:

  1. 扩张和侵蚀二元掩码以弥合轮廓片段之间的任何一个或两个像素间隙。
  2. 使用最大抑制将沿着形状边界的厚二元蒙版变成薄边。
  3. 正如前面在管道中使用的那样,使用 cvFindcontours 来识别闭合轮廓。可以测试由该方法识别的每个轮廓是否闭合。
  4. 作为此类问题的一般解决方案,我建议您尝试我的算法来找到给定点周围的闭合轮廓。使用固定检查主动分割
于 2015-12-22T07:33:18.883 回答