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我正在使用 Java Play 框架中的 AKKA Actors 创建一个 Web 套接字处理程序。我正在尝试解析消息并创建 JsonNode。我试过了

public void onReceive(Object message) throws Exception
{
    if (message instanceof String)
    {
        JsonNode clientMessage =Json.toJson(message.toString());
        System.out.println(clientMessage);//"{\"messageTxt\":\"hello\",\"id\":\"123\"}"

        ObjectMapper objectMapper = new ObjectMapper();

        try
        {
            JsonNode node = objectMapper.readValue(clientMessage, JsonNode.class);
            JsonNode messageNode = node.get("messageTxt");
            String messagec = messageNode.asText();
            System.out.println("message = " + messagec);

            JsonNode idNode = node.get("id");
            int id = idNode.asInt();
            System.out.println("id = " + id);
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
        /*
            out.tell( response, self());
        */
    }
}

我收到一个错误 

[error]  no suitable method found for readValue(com.fasterxml.jackson.databind.JsonNode,java.lang.Class<com.fasterxml.jackson.databind.JsonNode>)

[error]  (argument mismatch; com.fasterxml.jackson.databind.JsonNode cannot be converted to com.fasterxml.jackson.core.JsonParser))

如何将对象转换JsonNode为JsonParser对象？或者有没有更好的方法来创建 JSON/Map 对象。

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0 回答 0