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在家谱中，我们使用 DNA 来寻找匹配项。Y-DNA 发现父系匹配。执行此操作的 neo4j 查询（其中 RN 是一个人的唯一标识符）是：

MATCH (n{RN:1}) match p=n-[r:father*..22]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc

或者我们使用线粒体 DNA 进行母系匹配：

`MATCH (n{RN:1}) match p=n-[r:mother*..22]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc`

我的问题与 X 染色体 DNA 有关。一位父亲只给他的女儿一个 X 染色体，一位母亲给她所有的孩子一个。因此，我需要一个密码查询，当在最近的时间一代中有一个女儿时，它可以获取所有母亲的信息，但只有父亲的信息。后世若有子，则除父。我在节点中有一个属性“性别”，其值为 M 或 F。出生日期并不总是已知的，因此它不能用于确定方向性

我试过这个，但得到一个错误：

`MATCH (n{RN:1}) match p=n-[r:mother*..22|father*..1]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc`
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1 回答 1

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[更新]

[r:mother*..22|father*..1]语法是非法的。Cypher 查询中的关系最多可以有一个可变长度规范，并且它必须位于关系类型之后。（旁白：请注意，[:father*..1]这与 相同[:father]）。

这个在逻辑上似乎等效的查询对您有用吗？

MATCH pf=(n { RN:1 })-[:father]->()
MATCH pm=n-[:mother*..22]->()
WITH [pf] + COLLECT(pm) AS paths
UNWIND paths AS p
WITH LENGTH(p) AS generation, NODES(p) AS ancestors
WITH generation, ancestors, LAST(ancestors) AS m
RETURN m.RN AS RN, m.fullname AS FullName, m.sex AS Sex, m.bd AS BD, m.dd AS DD, generation,
  CASE WHEN left(m.bd,4)>'1930' AND rtrim(m.dd)='' THEN 'Y' ELSE 'N' END AS mtDNA_Candidate,
  reduce(srt2 ='|', q IN ancestors | srt2 + q.RN + '|' ) AS PathOrder
ORDER BY generation DESC, PathOrder DESC;
于 2015-12-14T21:47:16.693 回答