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我正在尝试实现webkitSpeechGrammarList。就像你在下面看到的。但是当我说它不在我的范围内时，grammar我会得到结果而不是"I didnt recognise that color".

var grammar = '#JSGF V1.0; grammar colors; public <color> = aqua | azure | beige | bisque | black | blue | brown | chocolate | coral | crimson | cyan | fuchsia | ghostwhite | gold | goldenrod | gray | green | indigo | ivory | khaki | lavender | lime | linen | magenta | maroon | moccasin | navy | olive | orange | orchid | peru | pink | plum | purple | red | salmon | sienna | silver | snow | tan | teal | thistle | tomato | turquoise | violet | white | yellow ;'
var recognition = new webkitSpeechRecognition();
var speechRecognitionList = new webkitSpeechGrammarList();
speechRecognitionList.addFromString(grammar, 1);
recognition.grammars = speechRecognitionList;
//recognition.continuous = false;
recognition.lang = 'en-US';
recognition.interimResults = false;
recognition.maxAlternatives = 1;



var diagnostic = document.querySelector('.output');
var bg = document.querySelector('html');


recognition.start();


recognition.onresult = function(event) {
  var color = event.results[0][0].transcript;
  diagnostic.textContent = 'Result received: ' + color + '.';
  bg.style.backgroundColor = color;
}

recognition.onspeechend = function() {
  recognition.stop();
}

recognition.onnomatch = function(event) {
  diagnostic.textContent = 'I didnt recognise that color.';
}

所以，因为这都是实验技术。我想知道..这真的实现了吗？我怎么知道？

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1 回答 1

3

此时语法被忽略。

于 2015-11-28T20:40:06.597 回答