Aster finding myself in the situation of wanting to disable a UIPickerView component and not finding any answers that uses the default functionality but tries to go around it by using labels or multiple UIPickerViews, I start poking around the UIPickerView structure in order to find a more direct approach to solve the problem by using the OS already present functionality.
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1 回答
1
所以这些是我的答案,我通过反复试验发现的,以及我使用它的方式:
方法:
- (void)dissableUIPickerViewComponent:(int)componentToDissable forPickerView:(UIPickerView *)pickerView{
NSArray *pickerViews = [[NSArray alloc] initWithArray:[pickerView subviews]];
UIView *mainSubview;
for (int count = 0; count < pickerViews.count; count++) {
UIView *temp = [pickerViews objectAtIndex:count];
if (temp.frame.size.height > 100) {
mainSubview = temp;
}
}
NSArray *componentSubview = [mainSubview subviews];
while ([[[[componentSubview objectAtIndex:componentToDissable] subviews] firstObject] superview].gestureRecognizers.count) {
[[[[[componentSubview objectAtIndex:componentToDissable]subviews]firstObject]superview] removeGestureRecognizer:[[[[[componentSubview objectAtIndex:componentToDissable]subviews]firstObject]superview].gestureRecognizers objectAtIndex:0]];
}
}
最佳通话地点:
- (void)viewDidAppear:(BOOL)animated{
[self dissableUIPickerViewComponent:0 myPickerView];
}
我希望这些将帮助其他发现自己处于与我相同的位置的人:)
于 2015-11-22T22:01:54.507 回答