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我的目标是从uicontrol文本框中获取用户的输入,对输入进行操作,然后将输出显示到另一个文本框。MATLAB给了我错误:

Error using
UnitConverter/lbs2kg
Too many input arguments.

Error in
UnitConverter>@(varargin)app.lbs2kg(varargin{:})
(line 22)
                'Callback',@app.lbs2kg,'String',app.inputMass); 
Error while evaluating UIControl Callback

这是我的代码:

classdef UnitConverter < handle


    properties
        Figure                  % Graphics handles
        DispInputMass
        DispOutputMass

        inputMass               %Variables/Class Properties
        outputMass 
    end


    methods

        function app = UnitConverter
            % This is the "constructor" for the class
            % It runs when an object of this class is created
            app.Figure = figure('Name','Unit Converter') ;

            app.DispInputMass = uicontrol('Style','edit',...
                'Callback',@app.lbs2kg,'String',app.inputMass);

            app.DispOutputMass = uicontrol(app.Figure,'Style','edit','Position'...
                 ,[168 100 47 26],'String','kg');
        end



        function lbs2kg(app,evt)
            app.inputMass = get(app.DispInputMass,'string');
            app.outputMass = app.inputMass*.453;
            set(app.DispOutputMass,'string',app.outputMass);
        end


    end
end
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1 回答 1

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回调方法实际上有 3 个输入 - MATLAB 抛出此错误,因为它试图将三个输入发送到您的回调,该回调被写入仅接受 2。这 3 个输入(按顺序)是:主对象(应用程序)、对象发送事件 (uicontrol) 和事件 (matlab.ui.eventdata.ActionData)。

您可以将代码更改为以下内容以使其正常工作:

function lbs2kg(app, obj, evt)
    app.inputMass = get(app.DispInputMass,'string');
    app.outputMass = app.inputMass*.453;
    set(app.DispOutputMass,'string',app.outputMass);
end

此外,您可以将函数的第一行更改为以下内容:

function lbs2kg(varargin)

在回调的第一行断点代码并调查 varargin 的内容。有关 varargin 的更多帮助,请参见此处 ( http://www.mathworks.com/help/matlab/ref/varargin.html )

于 2015-11-13T19:15:17.847 回答