我需要计算使用 Rijndael 加密的文件的大小。
根据本网站和谷歌上的其他答案,以下是计算加密数据长度的正确方法:
EL = UL + (BS - (UL Mod BS) Mod BS)
Where:
EL = Encrypted Length
UL = Unencrypted Length
BS = Block Size
在我的实例中,未加密的文件长度为 5,101,972 字节,我使用的是 128 位加密密钥,块大小为 16 字节。因此,方程为:
EL = 5101972 + (16 - (5101972 Mod 16) Mod 16)
EL = 5101972 + (16 - 4 Mod 16)
EL = 5101972 + (12 Mod 16)
EL = 5101972 + 12
EL = 5101984
给出一个长度为 5,101,984 字节的加密文件。
但是,加密后我的文件大小为 5,242,896,大小相差 140,912 字节!
现在..我显然做错了什么,但我无法弄清楚它是什么。下面是我的加解密测试代码,以及计算加密大小的方法:
private static void Enc(string decryptedFileName, string encryptedFileName)
{
PasswordDeriveBytes passwordDB = new PasswordDeriveBytes("ThisIsMyPassword", Encoding.ASCII.GetBytes("thisIsMysalt!"), "MD5", 2);
byte[] passwordBytes = passwordDB.GetBytes(128 / 8);
using (FileStream fsOutput = File.OpenWrite(encryptedFileName))
{
using(FileStream fsInput = File.OpenRead(decryptedFileName))
{
byte[] IVBytes = Encoding.ASCII.GetBytes("1234567890123456");
fsOutput.Write(BitConverter.GetBytes(fsInput.Length), 0, 8);
fsOutput.Write(IVBytes, 0, 16);
RijndaelManaged symmetricKey = new RijndaelManaged() { Mode = CipherMode.CBC,Padding=PaddingMode.Zeros};
ICryptoTransform encryptor = symmetricKey.CreateEncryptor(passwordBytes, IVBytes);
using (CryptoStream cryptoStream = new CryptoStream(fsOutput, encryptor, CryptoStreamMode.Write))
{
for (long i = 0; i < fsInput.Length; i += chunkSize)
{
byte[] chunkData = new byte[chunkSize];
int bytesRead = 0;
while ((bytesRead = fsInput.Read(chunkData, 0, chunkSize)) > 0)
{
cryptoStream.Write(chunkData, 0, chunkSize);
}
}
}
}
}
}
private static void Dec(string encryptedFileName, string decryptedFileName)
{
PasswordDeriveBytes passwordDB = new PasswordDeriveBytes("ThisIsMyPassword", Encoding.ASCII.GetBytes("thisIsMysalt!"), "MD5", 2);
byte[] passwordBytes = passwordDB.GetBytes(128 / 8);
using (FileStream fsInput = File.OpenRead(encryptedFileName))
{
using (FileStream fsOutput = File.OpenWrite(decryptedFileName))
{
byte[] buffer = new byte[8];
fsInput.Read(buffer, 0, 8);
long fileLength = BitConverter.ToInt64(buffer, 0);
byte[] IVBytes = new byte[16];
fsInput.Read(IVBytes, 0, 16);
RijndaelManaged symmetricKey = new RijndaelManaged() { Mode = CipherMode.CBC,Padding=PaddingMode.Zeros};
ICryptoTransform decryptor = symmetricKey.CreateDecryptor(passwordBytes, IVBytes);
using (CryptoStream cryptoStream = new CryptoStream(fsOutput, decryptor, CryptoStreamMode.Write))
{
for (long i = 0; i < fsInput.Length; i += chunkSize)
{
byte[] chunkData = new byte[chunkSize];
int bytesRead = 0;
while ((bytesRead = fsInput.Read(chunkData, 0, chunkSize)) > 0)
{
cryptoStream.Write(chunkData, 0, bytesRead);
}
}
fsOutput.SetLength(fileLength);
}
}
}
}
private static void CalcEncSize(string decryptedFileName)
{
FileInfo fi = new FileInfo(decryptedFileName);
if (fi.Exists)
{
long blockSize = 128/8;
long fileLength = fi.Length;
long encryptedSize = fileLength + ((blockSize - (fileLength % blockSize)) % blockSize);
encryptedSize += 24; //16 bytes for the IV, and 8 more for the filelength, both stored at the start of the file.
Console.WriteLine("Estimated Encryption Size: " + encryptedSize.ToString());
}
}
注意:在开始的计算中,我不包括我自己在加密文件开头用于存储原始文件长度的额外 24 个字节,以及 IV...我知道这一点,但没有想要使方程式变得不必要地复杂化。