r - 当 type="latex" 时，如何将观星表向左对齐？

Question

我在我的自动 rmarkdown pdf 文档中使用 stargazer 包来制作漂亮的表格。默认情况下，Stargazer 将其表格放置在页面的中心。如何让 stargazer 生成将表格向左对齐的乳胶代码？

这是我的意思的一个例子：

library(stargazer)

data_object <- structure(list(test = structure(c(1L, 1L, 2L, 2L), .Label = c("test1",  "test2"), class = "factor"), test2 = structure(1:4, .Label = c("1",        "2", "3", "4"), class = "factor")), .Names = c("test", "test2"), row.names = c(NA, -4L), class = "data.frame")

stargazer(data_object,title="table test",summary=FALSE,rownames=FALSE,type="latex",header=FALSE)

它产生的代码是：

\begin{table}[!htbp] \centering 
  \caption{table test} 
  \label{} 
\begin{tabular}{@{\extracolsep{5pt}} cc} 
\\[-1.8ex]\hline 
\hline \\[-1.8ex] 
test & test2 \\ 
\hline \\[-1.8ex] 
test1 & 1 \\ 
test1 & 2 \\ 
test2 & 3 \\ 
test2 & 4 \\ 
\hline \\[-1.8ex] 
\end{tabular} 
\end{table}

注意\centering. 我怎样才能改变它而不必改变乳胶代码本身？

Answer 1

看起来\centering是硬编码到函数中的。您可以做的是\centering使用sub（例如sub(" \\\\centering", "", out)）删除。

这是我使用的块。我曾经capture.output阻止stargazer输出我认为的中间结果。

<<results = "asis">>=
library(stargazer)

data_object <- structure(list(test = structure(c(1L, 1L, 2L, 2L), .Label = c("test1",  "test2"), class = "factor"), test2 = structure(1:4, .Label = c("1",        "2", "3", "4"), class = "factor")), .Names = c("test", "test2"), row.names = c(NA, -4L), class = "data.frame")

out <- capture.output(stargazer(data_object,title="table test",summary=FALSE,rownames=FALSE,type="latex",header=FALSE))
out <- sub(" \\\\centering", "", out)
cat(out)
@