我正在处理一个 JSON 结构,其输出如下:
{
"time": "2015-10-20T20:15:00.847Z",
"name": "meta.response.ean",
"level": "info",
"data1": {
"HotelListResponse": {
"customerSessionId": "0AB29024-F6D4-3915-0862-DB3FD1904C5A",
"numberOfRoomsRequested": 1,
"moreResultsAvailable": true,
"cacheKey": "-705f6d43:15086db3fd1:-4c58",
"cacheLocation": "10.178.144.36:7300",
"HotelList": {
"@size": 2,
"@activePropertyCount": 2,
"HotelSummary": [{
"hotelId": 132684,
"city": "Seattle",
"highRate": 159.0,
"lowRate": 159.0,
"rateCurrencyCode": "USD",
"RoomRateDetailsList": {
"RoomRateDetails": {
"roomTypeCode": 10351,
"rateCode": 10351,
"roomDescription": "Standard Room, 1 Queen Bed",
"RateInfos": {
"RateInfo": {
"@promo": false,
"ChargeableRateInfo": {
"@averageBaseRate": 159.0,
"@averageRate": 159.0,
"@currencyCode": "USD",
"@nightlyRateTotal": 159.0,
"@surchargeTotal": 26.81,
"@total": 185.81
}
}
}
}
}
}, {
"hotelId": 263664,
"city": "Las Vegas",
"highRate": 135.0,
"lowRate": 94.5,
"rateCurrencyCode": "USD",
"RoomRateDetailsList": {
"RoomRateDetails": {
"roomTypeCode": 373685,
"rateCode": 1238953,
"roomDescription": "Standard Room, 1 King Bed",
"RateInfos": {
"RateInfo": {
"@promo": true,
"ChargeableRateInfo": {
"@averageBaseRate": 135.0,
"@averageRate": 94.5,
"@currencyCode": "USD",
"@nightlyRateTotal": 94.5,
"@surchargeTotal": 9.45,
"@total": 103.95
}
}
}
}
}
}
]
}
}
},
"context": {
"X-Request-Id": "dca47992-b6cc-4b87-956c-90523c0bf3bb",
"host": "getaways-search-app2",
"thread": "http-nio-80-exec-12"
}
}
如您所见,这些是嵌套数组。关于递归地展平这些有很多讨论。我无法在HotelSummary
. 有任何想法吗?
- 我想将部分 JSON 展平为以下形式:
{
"customerSessionId":"0AB29024-F6D4-3915-0862-DB3FD1904C5A",
"numberOfRoomsRequested":1,
"moreResultsAvailable":"true",
"cacheKey":"-705f6d43:15086db3fd1:-4c58",
"cacheLocation":"10.178.144.36:7300",
"size":2,
"activePropertyCount":2,
"hotelId":132684,
"city":"Seattle",
"highRate":159.0,
"lowRate":159.0,
"rateCurrencyCode":"USD",
"roomTypeCode":10351,
"rateCode":10351,
"roomDescription":"Standard Room, 1 Queen Bed",
"promo":"false",
"averageBaseRate":159.0,
"averageRate":159.0,
"currencyCode":"USD",
"nightlyRateTotal":159.0,
"surchargeTotal":26.81,
"total":185.81
}
{
"customerSessionId":"0AB29024-F6D4-3915-0862-DB3FD1904C5A",
"numberOfRoomsRequested":1,
"moreResultsAvailable":"true",
"cacheKey":"-705f6d43:15086db3fd1:-4c58",
"cacheLocation":"10.178.144.36:7300",
"size":2,
"activePropertyCount":2,
"hotelId":263664,
"city":"Las Vegas",
"highRate":135.0,
"lowRate":94.5,
"rateCurrencyCode":"USD",
"roomTypeCode":373685,
"rateCode":1238953,
"roomDescription":"Standard Room, 1 King Bed",
"promo":"true",
"averageBaseRate":135.0,
"averageRate":94.5,
"currencyCode":"USD",
"nightlyRateTotal":94.5,
"surchargeTotal":9.45,
"total":103.95
}
- 我试过使用
flattenDict
类。我没有得到所需格式的输出。
def flattenDict(d, result=None):
if result is None:
result = {}
for key in d:
value = d[key]
if isinstance(value, dict):
value1 = {}
for keyIn in value:
value1[".".join([key,keyIn])]=value[keyIn]
flattenDict(value1, result)
elif isinstance(value, (list, tuple)):
for indexB, element in enumerate(value):
if isinstance(element, dict):
value1 = {}
index = 0
for keyIn in element:
newkey = ".".join([key,keyIn])
value1[".".join([key,keyIn])]=value[indexB][keyIn]
index += 1
for keyA in value1:
flattenDict(value1, result)
else:
result[key]=value
return result