尝试以下操作:
WITH MEMBER [Measures].[Parent %] AS
IIF(
[Nbh].[Nbh].CURRENTMEMBER IS [Nbh].[Nbh].[All]
,1
,[Measures].[Cad value] /
(
[Measures].[Cad value],
[Nbh].[Nbh].CurrentMember.Parent
)
), FORMAT_STRING = 'Percent'
SELECT
{[Measures].[Parent %]} ON 0,
[Nbh].[Nbh].[Nbh].AllMembers ON 1
FROM Cadastre;
包括IIF
是一种防御措施。如果您切换到显示AllMembers
完整的层次结构,则该All
成员将被包括在内。这是一个使用示例AdvWrks
:
WITH
MEMBER [Measures].[Parent %] AS
IIF
(
[Product].[Subcategory].CurrentMember
IS
[Product].[Subcategory].[All Products]
,1
,
[Measures].[Internet Sales Amount]
/
(
[Measures].[Internet Sales Amount]
,[Product].[Subcategory].CurrentMember.Parent
)
)
,FORMAT_STRING = 'Percent'
SELECT
NON EMPTY
{[Measures].[Parent %]} ON 0
,NON EMPTY
[Product].[Subcategory].ALLMEMBERS ON 1
FROM [Adventure Works];
以上返回以下内容:
没有IIF
表达式如下:
WITH
MEMBER [Measures].[Parent %] AS
[Measures].[Internet Sales Amount]
/
(
[Measures].[Internet Sales Amount]
,[Product].[Subcategory].CurrentMember.Parent
)
,FORMAT_STRING = 'Percent'
SELECT
NON EMPTY
{[Measures].[Parent %]} ON 0
,NON EMPTY
[Product].[Subcategory].ALLMEMBERS ON 1
FROM [Adventure Works];
由于缺乏远见,我们得到以下结果: