7

dismiss()加载 webview 后，我的代码需要什么来制作对话框？

public void onCreate(Bundle savedInstanceState) { 
            super.onCreate(savedInstanceState); 
            setContentView(R.layout.main); 
            CookieSyncManager.createInstance(this);
            CookieSyncManager.getInstance().startSync();
            webview = (WebView) findViewById(R.id.webview);
            webview.setWebViewClient(new homeClient());
            webview.getSettings().setJavaScriptEnabled(true);
            webview.getSettings().setPluginsEnabled(true);
            webview.loadUrl("http://google.com");

            ProgressDialog pd = ProgressDialog.show(Home.this, "", 
                    "Loading. Please wait...", true);

        }

我试过了

public void onPageFinshed(WebView view, String url){
        pd.dismiss();
    }

没用。

4

6 回答 6

16

:o webview.setWebViewClient(new homeClient()); 家庭客户端（）？？？？

尝试这个

...
...
...

webview = (WebView) findViewById(R.id.webview);
webview.setWebViewClient(new WebViewClient() {
            public boolean shouldOverrideUrlLoading(WebView view, String url) {              
                view.loadUrl(url);
                return true;
            }


          public void onPageFinished(WebView view, String url) {
                if (progressBar.isShowing()) {
                    progressBar.dismiss();
                }
            }
 webview.loadUrl("http://www.google.com");

}

更新:: 这是一个很好的例子。

Android WebView 和 Indeterminant Progress 解决方案

于 2010-07-19T18:43:05.117 回答
3

还行吧。

public class WordActivity extends Activity {

    private WebView webview;
    private ProgressDialog progressDialog;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.webview);
        Bundle objetbunble  = this.getIntent().getExtras(); 
        webview = (WebView) findViewById(R.id.webview);

        final Activity activity = this;

        webview.getSettings().setJavaScriptEnabled(true);

        webview.setWebViewClient(new WebViewClient() {
            public boolean shouldOverrideUrlLoading(WebView view, String url) {              
                view.loadUrl(url);
                return true;
            }
            public void onLoadResource (WebView view, String url) {
                if (progressDialog == null) {
                    progressDialog = new ProgressDialog(activity);
                    progressDialog.setMessage("Chargement en cours");
                    progressDialog.show();
                }
            }
            public void onPageFinished(WebView view, String url) {
                if (progressDialog.isShowing()) {
                    progressDialog.dismiss();
                    progressDialog = null;
                }
            }
        }); 
        webview.loadUrl("http://www.example.com");
    }


}
于 2010-10-22T00:16:13.580 回答
3

@Jorgesys 这不是 100% 准确的。如果您在一个页面中有多个 iframe，您将有多个 onPageFinished（和 onPageStarted）。如果您有多个重定向，它也可能会失败。我认为这种方法可以解决所有问题：

boolean loadingFinished = true;
boolean redirect = false;

mWebView.setWebViewClient(new WebViewClient() {

   @Override
   public boolean shouldOverrideUrlLoading(WebView view, String urlNewString) {
       if (!loadingFinished) {
          redirect = true;
       }

   loadingFinished = false;
   webView.loadUrl(urlNewString);
   return true;
   }

   @Override
   public void onPageStarted(WebView view, String url) {
        loadingFinished = false;
        //SHOW LOADING IF IT ISNT ALREADY VISIBLE  
    }

   @Override
   public void onPageFinished(WebView view, String url) {
       if(!redirect){
          loadingFinished = true;
       }

       if(loadingFinished && !redirect){
         //HIDE LOADING IT HAS FINISHED
       } else{
          redirect = false; 
       }

    }
});
于 2011-03-02T20:23:54.100 回答
2

你是如何访问pd的onPageFinshed()？（你确定它是在页面加载时实际调用的吗？）

在您的onCreate()中，尝试传递pd给您的homeClient，以便homeClient处理关闭对话框。

您的 homeClient 应如下所示：

private class homeClient extends WebViewClient {

    private ProgressDialog pd;

    public homeClient(ProgressDialog pd) {
        this.pd = pd;
    }

    @Override 
    public boolean shouldOverrideUrlLoading(WebView view, String url) {           
        view.loadUrl(url); 
        return true; 
    } 

    @Override
    public void onPageFinished (WebView view, String url) {
        if (pd.isShowing()) {
            pd.dismiss();
        }
    }
}

在你的onCreate()：

ProgressDialog pd = ProgressDialog.show(Fbook.this, "", 
                "Loading. Please wait...", true);
webview.setWebViewClient(new homeClient(pd));
于 2010-07-19T18:42:57.070 回答
0 
wv1.setWebViewClient(new WebViewClient() {
            public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
                Toast.makeText(Entertainment.this, description, Toast.LENGTH_SHORT).show();
            }

            @Override
            public void onPageStarted(WebView view, String url, Bitmap favicon)
            {
                progressDialog.show();
            }


            @Override
            public void onPageFinished(WebView view, String url) {
                progressDialog.dismiss();
                String webUrl = wv1.getUrl();

            }

        });

    wv1.loadUrl(url);

上面的代码将为您导航到 web 视图中的每个传入链接显示一个进度对话框。

于 2016-05-23T16:31:08.333 回答
0

如果您只是想在 WebView 中加载网页之前显示进度。您可以简单地请求窗口功能进度，例如

getWindow().requestFeature(Window.FEATURE_PROGRESS);

前setContentView(R.layout.blahblah);

并在 onProgressChanged 中显示进度，例如

 final Activity context= this;
 webview.setWebChromeClient(new WebChromeClient() 
 {
   public void onProgressChanged(WebView webView, int progress) 
   {
     activity.setProgress(progress * 1000);
   }
 });

如果你想添加你自己的ProgressDialog 然后使用 WebviewClient

webView.setWebViewClient(new WebViewClient() {
    ProgressDialog rogressDialog ;
    @Override
    public void onPageStarted(WebView view, String url, Bitmap bitmap) {
        progressDialog = ProgressDialog.show(context, "Loading...", "Please wait...");//where context = YourActivity.this;
        super.onPageStarted(view, url, bitmap);
    }

    @Override
    public void onPageFinished(WebView view, String url) {
        progressDialog .dismiss();
        super.onPageFinished(view, url);
    }
});

webView.loadUrl(url);
于 2015-08-05T08:08:28.320 回答