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在 XAML 中,在 Windows.Resources 中,我有 2 个 DataTemplate

<Window.Resources>

<DataTemplate x:Key="HorribleTemplate">
    (...Horrible Stuff here )
</DataTemplate>

<DataTemplate x:Key="AwesomeTemplate">
    (...Awesome Stuff here )
</DataTemplate>

</Window.Resources>

我创建了一个 ListView 控件,默认情况下它使用 HorribleTemplate 作为其 CellTemplate。有没有办法在运行时将 Listview 的 CellTemplate 更改为 AwesomeTemplate?

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1 回答 1

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使用触发器时,需要使用 Style 设置初始属性值,否则新值不会优先,它会继续使用旧值。发生这种情况是因为属性值优先。

使用触发器:

<Window x:Class="WpfListBox._32674841.Win32674841"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:sys="clr-namespace:System;assembly=mscorlib"
        Title="Win32674841" Height="300" Width="300">

    <Window.Resources>

        <DataTemplate x:Key="HorribleTemplate" DataType="{x:Type sys:String}">
                <TextBlock Background="CadetBlue" Text="{Binding}"/>
        </DataTemplate>

        <DataTemplate x:Key="AwesomeTemplate" DataType="{x:Type sys:String}">
            <TextBlock Background="Aqua" Text="{Binding}"/>
        </DataTemplate>

    </Window.Resources>

    <StackPanel>
        <Button Content="Change" Click="Button_Click"/>
        <ListView x:Name="ListView1">
            <ListView.Style>
                <Style TargetType="ListView">
                    <Setter Property="ItemTemplate" Value="{StaticResource HorribleTemplate}"/>
                    <Style.Triggers>
                        <Trigger Property="IsMouseOver" Value="True">
                            <Setter Property="Background" Value="Red"/>
                            <Setter Property="ItemTemplate" Value="{StaticResource AwesomeTemplate}"/>
                        </Trigger>
                    </Style.Triggers>
                </Style>
            </ListView.Style>
        </ListView>
    </StackPanel>

</Window>

从代码隐藏:

using System;
using System.Collections.Generic;
using System.Windows;
using System.Windows.Controls;

namespace WpfListBox._32674841
{
    /// <summary>
    /// Interaction logic for Win32674841.xaml
    /// </summary>
    public partial class Win32674841 : Window
    {
        public Win32674841()
        {
            InitializeComponent();

            ListView1.ItemsSource = DataStore.Names;
        }

        private void Button_Click(object sender, RoutedEventArgs e)
        {
            ListView1.ItemTemplate = (DataTemplate)this.Resources["AwesomeTemplate"];
        }
    }
    public class DataStore
      {
         public static List<String> Names { get { return new List<string>() { "Anjum" }; } }
      }


}
于 2015-09-20T07:16:59.140 回答