15

我正在尝试使用此代码获取 SSID

import Foundation
import SystemConfiguration.CaptiveNetwork

public class SSID {
    class func getSSID() -> String{
        var currentSSID = ""
        let interfaces = CNCopySupportedInterfaces()
        if interfaces != nil {
            let interfacesArray = interfaces.takeRetainedValue() as [String : AnyObject]
            if interfacesArray.count > 0 {
                let interfaceName = interfacesArray[0] as String
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interfaceName)
                if unsafeInterfaceData != nil {
                    let interfaceData = unsafeInterfaceData.takeRetainedValue() as Dictionary!
                    currentSSID = interfaceData[kCNNetworkInfoKeySSID] as! String
                    let ssiddata = NSString(data:interfaceData[kCNNetworkInfoKeySSIDData]! as! NSData, encoding:NSUTF8StringEncoding) as! String
                    // ssid data from hex
                    print(ssiddata)
                }
            }
        }
        return currentSSID
    }
}

但是在这一行出现错误 let interfacesArray = interfaces.takeRetainedValue() as [String : AnyObject]

错误是

Value of type 'CFArray?' has no member 'takeRetainedValue'

谢谢你的帮助

4

10 回答 10

27

这可能会对您有所帮助（在 Swift 2 上测试）：

import Foundation
import SystemConfiguration.CaptiveNetwork

public class SSID {
    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces) {
                let interfaceName: UnsafePointer<Void> = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)")
                if unsafeInterfaceData != nil {
                    let interfaceData = unsafeInterfaceData! as Dictionary!
                    currentSSID = interfaceData["SSID"] as! String
                }
            }
        }
        return currentSSID
    }
}

我从 Ray Wenderlich 的网站上获取并修改了代码（曾经在这里： Retrieve SSID in iOS9但现在特定线程已从网站中删除）

iOS 12

您必须启用从功能访问 WiFi 信息。

重要 要在 iOS 12 及更高版本中使用此功能，请在 Xcode 中为您的应用启用访问 WiFi 信息功能。当您启用此功能时，Xcode 会自动将 Access WiFi Information 权利添加到您的权利文件和 App ID 中。文档链接

斯威夫特4.2

public class SSID {
    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces) {
                let interfaceName: UnsafeRawPointer = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString)
                if let interfaceData = unsafeInterfaceData as? [String: AnyObject] {
                    currentSSID = interfaceData["SSID"] as! String
                    let BSSID = interfaceData["BSSID"] as! String
                    let SSIDDATA = interfaceData["SSIDDATA"] as! String
                    debugPrint("ssid=\(currentSSID), BSSID=\(BSSID), SSIDDATA=\(SSIDDATA)")
                }
            }
        }
        return currentSSID
    }
}
于 2015-09-24T17:40:32.540 回答
14

这是我的解决方案 Swift 3 iOS 10，它适用于Xcode 8 

import Foundation

import SystemConfiguration.CaptiveNetwork

class network : NSObject {

    func getSSID() -> String? {

        let interfaces = CNCopySupportedInterfaces()
        if interfaces == nil {
            return nil
        }

        let interfacesArray = interfaces as! [String]
        if interfacesArray.count <= 0 {
            return nil
        }

        let interfaceName = interfacesArray[0] as String
        let unsafeInterfaceData =     CNCopyCurrentNetworkInfo(interfaceName as CFString)
        if unsafeInterfaceData == nil {
            return nil
        }

        let interfaceData = unsafeInterfaceData as! Dictionary <String,AnyObject>

        return interfaceData["SSID"] as? String
    }

}

要使用它：

let wifiName = network().getSSID()

    guard wifiName != nil else {

        //// TODO: Alert -----
        print("no wifi name")

        return
    }


    print("my network name is: \(wifiName!)")

PS：注意它不适用于模拟器

于 2016-09-18T08:13:30.970 回答
8

目前提出的所有解决方案似乎都相当复杂，带有丑陋的不安全演员表。

我能够制作出如此简洁的解决方案（根本没有黑魔法）：

import Foundation
import SystemConfiguration.CaptiveNetwork

func getSSID() -> String? {
    var ssid: String?
    if let interfaces = CNCopySupportedInterfaces() as NSArray? {
        for interface in interfaces {
            if let interfaceInfo = CNCopyCurrentNetworkInfo(interface as! CFString) as NSDictionary? {
                ssid = interfaceInfo[kCNNetworkInfoKeySSID as String] as? String
                break
            }
        }
    }
    return ssid
}
于 2016-06-16T10:25:51.560 回答
5

在 Swift 3 中（在真实设备和模拟器中工作）：

import SystemConfiguration.CaptiveNetwork

internal class SSID {
    class func fetchSSIDInfo() ->  String {
        var currentSSID = ""
        if let interfaces:CFArray = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces){
                let interfaceName: UnsafeRawPointer = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString)
                if unsafeInterfaceData != nil {

                    let interfaceData = unsafeInterfaceData! as Dictionary!
                    currentSSID = ((interfaceData as? [String : AnyObject])?["SSID"])! as! String

                }
            }
        }
        return currentSSID
    }
}

用法：

SSID.fetchSSIDInfo()

//will return "" if no connected wifi or running in simulator
于 2016-10-11T19:21:42.730 回答
2

斯威夫特 4 版本

import SystemConfiguration.CaptiveNetwork


func getSSID() -> String? {
    guard let interface = (CNCopySupportedInterfaces() as? [String])?.first,
        let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interface as CFString) as? [String: Any],
        let ssid = unsafeInterfaceData["SSID"] as? String else{
            return nil
    }
    return ssid
}
于 2018-07-24T13:33:11.867 回答
1

在 swift 2 中，您不必调用takeRetainedValue.

将代码替换interfaces.takeRetainedValue() as [String : AnyObject]为Array(arrayLiteral: interfaces).

还记得把代码interfacesArray[0] as String改成String(interfacesArray[0]).

完整代码：</p> 

public class SSID {
class func getSSID() -> String{
    var currentSSID = ""
    let interfaces = CNCopySupportedInterfaces()
    if interfaces != nil {
        let interfacesArray = Array(arrayLiteral: interfaces)
        if interfacesArray.count > 0 {
            let interfaceName =  String(interfacesArray[0])
            let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interfaceName)
            if unsafeInterfaceData != nil {
                let interfaceData = unsafeInterfaceData.takeRetainedValue() as Dictionary!
                currentSSID = interfaceData[kCNNetworkInfoKeySSID] as! String
                let ssiddata = NSString(data:interfaceData[kCNNetworkInfoKeySSIDData]! as! NSData, encoding:NSUTF8StringEncoding) as! String
                // ssid data from hex
                print(ssiddata)
            }
        }
    }
    return currentSSID
}

}

于 2015-09-19T05:25:42.623 回答
1

在 Swift 中获取 WiFi 网络 SSID 和 BSSID

SystemConfiguration我已经使用该框架看到了这个非常流行的问题的很多版本。通读这个答案列表，我发现它们无处不在。不安全的位转换，魔术字符串，奇怪的强制。任何时候 API 返回CFArray或CFDictionary使用免费桥接来获取NS{Array,Dictionary}. 它允许您避免CoreFoundation. 此外，您应该使用标题中为 SSID 和 BSSID 字典值定义的常量。这里绝对不需要 Unsafe 类型，所有的数据类型都是定义良好的。也就是说，此代码的 CaptiveNetwork 版本在 iOS 14 中已弃用，建议您改用该NetworkExtension框架。

NE热点网络

import NetworkExtension

NEHotspotNetwork.fetchCurrent { hotspotNetwork in
    if let ssid = hotspotNetwork?.ssid {
        print(ssid)
    }
}

已弃用 - CaptiveNetwork 方法

import SystemConfiguration.CaptiveNetwork

func getWiFiNetwork() -> (ssid: String, bssid: String)?
{
    var wifiNetwork: (ssid: String, bssid: String)?
    if let interfaces = CNCopySupportedInterfaces() as NSArray? {
        for interface in interfaces {
            let name = interface as! CFString
            if let interfaceData = CNCopyCurrentNetworkInfo(name) as NSDictionary? {
                if let ssid = interfaceData[kCNNetworkInfoKeySSID] as? String,
                    let bssid = interfaceData[kCNNetworkInfoKeyBSSID] as? String {
                    wifiNetwork = (ssid: ssid, bssid: bssid)
                }
            }
        }
    }
    
    return wifiNetwork
}

权限 - CoreLocation

就用户权限而言，您有可能，但您需要在CNCopyCurrentNetworkInfo或fetchCurrent文档中定义的四个之一- 在大多数情况下，我假设您需要添加 CoreLocation 并请求使用用户位置的权限。例如，Privacy - Location When In Use Usage Description在 Info.plist 中需要说明您需要用户位置的原因，然后您必须拨打电话以请求用户授权对话框。

    import CoreLocation

    CLLocationManager().requestWhenInUseAuthorization()

权利

您的应用程序还需要授权 -在项目的Signing and Capabilities部分中com.apple.developer.networking.wifi-info添加，称为Access WiFi Information。使用方法时，需要额外的网络扩展权利。NEHotspotNetwork

于 2020-12-04T08:44:07.507 回答
0

以下函数返回wifi名称和Mac地址

    func getNetworkInfo()->(success:Bool,ssid:String,mac:String){
      var currentSSID:String = ""
      var macAdrees:String = ""
      var succes:Bool = false
      let interfaces:CFArray! = CNCopySupportedInterfaces()
      for i in 0..<CFArrayGetCount(interfaces){
        let interfaceName: UnsafePointer<Void>
        =  CFArrayGetValueAtIndex(interfaces, i)
        let rec = unsafeBitCast(interfaceName, AnyObject.self)
        let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)")
        if unsafeInterfaceData != nil {
            let interfaceData = unsafeInterfaceData! as Dictionary!
            currentSSID = interfaceData["SSID"] as! String
            macAdrees = interfaceData["BSSID"] as! String
            succes = true
        } else {
            currentSSID = ""
        }
    }

    return (succes, currentSSID, macAdrees)
}

这段代码工作正常。你会在你的开发目标中注意到一些警告 >= iOS9

于 2016-03-23T16:21:17.337 回答
0

您可以使用更新的 Swift 标准 @japes 答案找到另一个答案，该标准同时支持Swift 3和Swift 4。""在模拟器上返回空。

import SystemConfiguration.CaptiveNetwork

internal class SSID {

    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces){
                let interfaceName = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                guard let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString) else {
                    return currentSSID
                }
                guard let interfaceData = unsafeInterfaceData as? [String: Any] else {
                    return currentSSID
                }
                guard let SSID = interfaceData["SSID"] as? String else {
                    return currentSSID
                }
                currentSSID = SSID
            }
        }
        return currentSSID
    }

}
于 2018-03-16T14:23:20.137 回答
0

https://stackoverflow.com/users/3108877/rob的答案——更短的版本

func getSSID() -> String? {
        if let interface = (CNCopySupportedInterfaces() as? [String])?.first,
            let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interface as CFString) as? [String: Any],
            let ssid = unsafeInterfaceData["SSID"] as? String {
            return ssid
        }
        return nil
    }
于 2017-07-18T06:05:43.577 回答