0

我在 WebGL 中遇到 parse + unity 的问题，它在 android 或 pc 中运行良好，但是当我在 web 中测试时出现此错误

exception thrown: SyntaxError: Failed to execute 'setRequestHeader' on 'XMLHttpRequest': 'sme 0' is not a valid HTTP header field value.,Error: Failed to execute 'setRequestHeader' on 'XMLHttpRequest': 'sme 0' is not a valid HTTP header field value.
    at Error (native)
    at _JS_WebRequest_SetRequestHeader (http://localhost:60265/Release/Web.js:1:299623)
    at aAg (http://localhost:60265/Release/Web.js:28:772491)
    at YBc (http://localhost:60265/Release/Web.js:23:638406)
    at Array.Are (http://localhost:60265/Release/Web.js:24:499286)
    at U4p (http://localhost:60265/Release/Web.js:5:760172)
    at Z4p (http://localhost:60265/Release/Web.js:5:770191)
    at bXo (http://localhost:60265/Release/Web.js:9:582682)
    at Array.vWo (http://localhost:60265/Release/Web.js:9:501983)
    at Array.dap (http://localhost:60265/Release/Web.js:9:944092)Module.printErr @ (index):34Browser.mainLoop.runIter @ Web.js:1Browser_mainLoop_runner @ Web.js:1

你知道这是否是一个错误吗？我正在使用个人版的统一

在 chrome 和 firefox 中测试过，在这两种情况下都出现错误

已编辑

此代码破坏了 WebGL 游戏

ParseUser.LogInAsync ("aaaaaa", "bbbbbb").ContinueWith (t => {
        if (t.IsFaulted || t.IsCanceled){

            ParseUser user = new ParseUser ();
            user ["username"] = "aaaaaa";
            user ["password"] = "bbbbbb";


            ParseUser.LogOutAsync().ContinueWith(c=>{
                user.SignUpAsync().ContinueWith(b =>{
                    if (b.IsFaulted || b.IsCanceled){
                        print ("signup fail");
                    }else{
                        print ("signup success");
                    }
                });
            });



        }else{
            print ("login success");
        }
    });
4

0 回答 0