0

问题

我想:

p <= (d-a) * b

尝试通过使用 DSP48E1 而不是简单地编写p <= (d-a) * bplus 来直接实例化 DSP 块,这有助于我理解这个块在未来是如何工作的。到目前为止,我的运气并不好。

参考这篇文章:

http://www.xilinx.com/support/documentation/user_guides/ug479_7Series_DSP48E1.pdf

试图

这些是我当前的设置:

a <= std_logic_vector(to_unsigned(5, 30));
b <= std_logic_vector(to_unsigned(1, 18));
d <= std_logic_vector(to_unsigned(20, 25));

    dsp : DSP48E1
    generic map (
        USE_DPORT => True,
        ALUMODEREG => 0, 
        CARRYINREG => 0,
        CARRYINSELREG => 0,
        CREG => 0
        )
    port map(
        clk => clk,
        acin => std_logic_vector(to_unsigned(1, 30)), -- cascaded data input
        alumode => "0000", -- control bits to select logic unit inputs
        bcin => std_logic_vector(to_unsigned(1, 18)), -- cascaded data input 
        carrycascin => '0', -- cascaded data input
        carryin => '0',  -- carry input
        carryinsel => "000", -- selects carry source
        cea1 => '1', -- clock enable if AREG = 2 or INMODE0 = 1
        cea2 => '1', -- clock enable if AREG = 1 or 2
        cead => '1', -- clock enable for AD pipeline register
        cealumode => '0', -- clock enable for ALUMODE --0
        ceb1 => '1', -- clock enable if BREG = 1 or INMODE4 = 1
        ceb2 => '1', -- clock enable if BREG = 1 or 2
        cec => '0', -- clock enable for C
        cecarryin => '0', -- clock enable
        cectrl => '0', -- clock enable for OPMODE and CARRYINSEL ctrl registers
        ced => '1', -- clock enable for D
        ceinmode => '0',-- **** clock enable input registers
        cem => '0', -- clock enable for the post multiply M register and the internal multiply round CARRYIN register
        cep => '1', -- clock enable 
        inmode => "01101", -- *selects functionality of preadder [3] = sign, [4] = B multiplier sel
        multsignin => '0', -- MACC extension sign
        opmode =>  "0000101", -- *** Control input to A, Y and Z multiplexers
        pcin => std_logic_vector(to_unsigned(1, 48)), -- cascade input
        rsta => rst,
        rstallcarryin => '0',
        rstalumode => '0',
        rstb => rst,
        rstc => '0',
        rstctrl => rst,
        rstd => rst,
        rstinmode => rst,
        rstm => rst,
        rstp => rst,
        a => a,--_dsp, -- bits 29:25 used in second stage preadder 
        b => b,--_dsp,
        c => c_dsp,
        d => d,--_dsp,
        p => p_dsp
    );

p = 0即使我强迫我也总是得到d = 20, a = 5, b = 1

我想我应该保留ALUMODEand OPMODE0因为我跳过了最后阶段,只想要一个直接的减法和乘法。

相片

数字信号处理器

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1 回答 1

2

查看DSP48E1 用户指南第 34 页中的表 2-7。

您当前的配置在后加器处执行P = Z + X + Y + CINZ = 0X = 0Y = 0。你看到这里的问题了吗?

这些OPMODE信号控制多路复用器的值。你想要OPMODE(6 downto 4) = "000", 以便Z保持它的空值。但是,您要OPMODE(3 downto 0) = "0101"设置X/Y为乘数输出MALUMODE应该保持它的当前值,这很好。

于 2015-08-03T14:48:49.470 回答