此代码在codepad.org提供的 Racket Scheme 中有效,在显示“意外返回”消息之前在连续的行上显示数字 1、2 和 3,但在ideone.com使用 Chicken Scheme 相同的代码失败,我不'不明白 Chicken Scheme 提供的错误信息。我怎样才能使它与鸡计划一起工作?
(define-syntax define-generator
(lambda (x)
(syntax-case x (lambda)
((stx name (lambda formals e0 e1 ...))
(with-syntax ((yield (datum->syntax-object (syntax stx) 'yield)))
(syntax (define name
(lambda formals
(let ((resume #f) (return #f))
(define yield
(lambda args
(call-with-current-continuation
(lambda (cont)
(set! resume cont)
(apply return args)))))
(lambda ()
(call-with-current-continuation
(lambda (cont)
(set! return cont)
(cond (resume (resume))
(else (let () e0 e1 ...)
(error 'name "unexpected return"))))))))))))
((stx (name . formals) e0 e1 ...)
(syntax (stx name (lambda formals e0 e1 ...)))))))
(define-generator (test-gen)
(yield 1)
(yield 2)
(yield 3))
(define t (test-gen))
(display (t)) (newline)
(display (t)) (newline)
(display (t)) (newline)
(display (t)) (newline)