java - 在知道引号的情况下拆分/标记/扫描字符串

Question

Java中是否有用于拆分字符串的默认/简单方法，但要注意引号或其他符号？

例如，给定以下文本：

There's "a man" that live next door 'in my neighborhood', "and he gets me down..."

获得：

There's
a man
that
live
next
door
in my neighborhood
and he gets me down

Answer 1

像这样的东西适用于您的输入：

    String text = "There's \"a man\" that live next door "
        + "'in my neighborhood', \"and he gets me down...\"";

    Scanner sc = new Scanner(text);
    Pattern pattern = Pattern.compile(
        "\"[^\"]*\"" +
        "|'[^']*'" +
        "|[A-Za-z']+"
    );
    String token;
    while ((token = sc.findInLine(pattern)) != null) {
        System.out.println("[" + token + "]");
    }

上面的打印（如在 ideone.com 上看到的）：

[There's]
["a man"]
[that]
[live]
[next]
[door]
['in my neighborhood']
["and he gets me down..."]

它使用Scanner.findInLine，其中正则表达式模式是以下之一：

"[^"]*"      # double quoted token
'[^']*'      # single quoted token
[A-Za-z']+   # everything else

毫无疑问，这并不总是 100% 有效。可以嵌套引号等的情况将很棘手。

参考

• 正则表达式.info/Character 类

Answer 2

根据您的逻辑值得怀疑，您可以区分撇号和单引号，There's即in my neighborhood

如果您想要上面的内容，则必须开发某种配对逻辑。我在想正则表达式。或某种两部分解析。