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我在上下文菜单中添加了一个按钮,仅当您在 Project Explorer 窗口中单击鼠标右键时才执行。我希望能够在 Project Explorer 窗口中抓取每个项目并抓取 ProjectName 和 ProjectLocation 并将其单独放入一个对象中并返回新的对象数组。

我找不到访问所需信息的方法。

插件.xml

<extension point="org.eclipse.ui.menus">
    <menuContribution locationURI="popup:org.eclipse.ui.navigator.ProjectExplorer#PopupMenu">
      <command commandId="helloworld.sample"
        label="Hello World" style="push">
      </command>
    </menuContribution>
  </extension>
  <extension point="org.eclipse.ui.commands">
    <command defaultHandler="helloworld.handler.samplehandler"
      id="helloworld.sample" name="Sample">
    </command>
  </extension>

样本处理程序.java

IWorkbenchPage page = PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage();

IWorkbenchPart viewpart  = page.findView("org.eclipse.ui.navigator.ProjectExplorer");

Tree tree = (Tree) ((TreeViewer) viewpart.getSite().getSelectionProvider()).getControl(); 
TreeItem[] selTree = tree.getSelection();

我觉得好像 tree 或 selTree 会有我想要的信息,但我找不到它。有什么帮助吗?

4

1 回答 1

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使用来自选择提供者的选择数据:

IStructuredSelection sel =   
     (IStructuredSelection)viewpart.getSite().getSelectionProvider().getSelection(); 

Object selObj = sel.getFirstElement();

IProject project =
   (IProject)Platform.getAdapterManager().getAdapter(selObj, IProject.class);

... might return null if selection is not the project

String name = project.getName();

IPath location = project.getLocation();

要让所有项目使用:

IWorkspace workspace = ResourcesPlugin.getPlugin().getWorkspace();

IProject [] projects = workspace.getRoot().getProjects();
于 2015-07-15T19:33:20.860 回答