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我需要将图像上传到自定义服务器。我有这样的代码：

NSString* boundary = @"blablablablabla";
NSString* boundaryString = [NSString stringWithFormat:@"\r\n--%@\r\n", boundary];
NSString* boundaryStringFinal = [NSString stringWithFormat:@"\r\n--%@--\r\n", boundary];

NSMutableData* postData = [NSMutableData dataWithCapacity:[imageData length] + 1024];

NSString* s = [NSString stringWithFormat:@"Content-Disposition: form-data; name=\"s\"\r\n\r\n%@\r\n", @"addimage"];
NSString* ad = [NSString stringWithFormat:@"Content-Disposition: form-data; name=\"ad\"\r\n\r\n%@\r\n", adIdx];
NSString* u = [NSString stringWithFormat:@"Content-Disposition: form-data; name=\"u\"\r\n\r\n%@\r\n", uid];

[postData appendData:[boundaryString dataUsingEncoding:NSUTF8StringEncoding]];
[postData appendData:[s dataUsingEncoding:NSUTF8StringEncoding]];
[postData appendData:[ad dataUsingEncoding:NSUTF8StringEncoding]];
[postData appendData:[u dataUsingEncoding:NSUTF8StringEncoding]];

[postData appendData:[boundaryString dataUsingEncoding:NSUTF8StringEncoding]];
[postData appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"image\";\r\nfilename=\"image.jpg\"\r\nContent-Type: image/jpg\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
[postData appendData:imageData];
[postData appendData:[boundaryStringFinal dataUsingEncoding:NSUTF8StringEncoding]];

NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http:a.b.c/d.php"]];
[request setHTTPMethod:@"POST"];

NSString* dataLength = [NSString stringWithFormat:@"%d", [postData length]];
[request addValue:[NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary] forHTTPHeaderField:@"Content-Type"];
[request addValue:@"a.b.c" forHTTPHeaderField:@"Host"];
[request addValue:dataLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];

[NSURLConnection connectionWithRequest:request delegate:self];

它看起来不错，但为了响应这个请求，我有这样的行：“缺少参数 u”。有人可以告诉我问题出在哪里吗？

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1 回答 1

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该missing parameter u消息几乎肯定来自服务器上的 PHP。我认为它应该在其中一种"u"\r\n\r\n结构中。你需要知道服务器期望什么来解决它。

我建议您将发布请求转储为字符串，粘贴到浏览器中，看看您是否可以让它工作。这样，您可以确保您了解请求的正确形式，以便您可以在代码中构建它。

于 2010-06-25T13:02:30.880 回答