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invalid property exception当我试图在我的表单对象中绑定我的模型对象中的集合时，我得到了一个。我正在尝试一些技巧，现在我认为问题在于 spring MVC 的休眠会话，所以在控制器中我编辑了 create 函数，以便在我的表单保存之前，我尝试获取会话并获取 typesite 的列表，但仍然得到相同的错误：

org.springframework.beans.InvalidPropertyException: Invalid property ‘siteesTypeSite[idTypeSite]’ of bean class [model.Sites]:
Property referenced in indexed property path ‘siteesTypeSite[idTypeSite]’ is neither an array nor a List nor a Map; returned value was [2]

我的映射有问题吗？

Sites.java 映射

public class Sites implements java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;

@JsonBackReference("site-typeSite")
@LazyCollection(LazyCollectionOption.FALSE)
@ManyToOne
@JoinColumn(name = “idTypeSite”) 
private TypeSites siteesTypeSite;
Getter/setters
}

TypeSites.java 映射：

public class TypeSites implements java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name="idTypeSite")
private int idTypeSite;

private String typeSite;

@LazyCollection(LazyCollectionOption.FALSE)
@JsonManagedReference("site-typeSite")
@OneToMany(mappedBy = “siteesTypeSite”,fetch = FetchType.LAZY) 
// private Set<Sites> sitees= new HashSet<Sites>(0);
private List<Sites> sitees = new AutoPopulatingList<Sites>(Sites.class);
Getter/setters
}

控制器类：

@RequestMapping(method = RequestMethod.POST, produces = "application/json")
public ResponseEntity<?> create(
                   @ModelAttribute("site") @Valid Sites site,
                   @ModelAttribute("typeSites")  TypeSites typeSites,
                   @RequestParam(required = false) String searchFor,
                   @RequestParam(required = false, 
                   defaultValue = DEFAULT_PAGE_DISPLAYED_TO_USER) int page,
                                        Locale locale) {
ServletRequestAttributes attr = (ServletRequestAttributes) RequestContextHolder.currentRequestAttributes();
HttpSession session = attr.getRequest().getSession();
TypeSites existingTypeSites = (TypeSites) ((Session) session).get(TypeSites.class, site.getSiteesTypeSite().getIdTypeSite());
site.setSiteesTypeSite(existingTypeSites);

siteService.save(site);
            }

Angularjs 代码：

$scope.createObject = function (newObjectForm) {
if (!newObjectForm.$valid) {
$scope.displayValidationError = true;
return;
}
$scope.lastAction = ‘create';
var url = $scope.url;
var config = {headers: {‘Content-Type': ‘application/x-www-form-urlencoded; charset=UTF-8′}};
$scope.addSearchParametersIfNeeded(config, false);
$scope.startDialogAjaxRequest();
$scope.sites.siteesTypeSite =JSON.parse($scope.sites.siteesTypeSite);
$http.post(url, $.param($scope.sites), config)
.success(function (data) {
$scope.finishAjaxCallOnSuccess(data, “#addObjectsModal”, false);
})
.error(function(data, status, headers, config) {
$scope.handleErrorInDialogs(status);
});
};

JSP：在这里我调用另一个角度控制器来获取选择上的类型站点列表

    <div   ng-controller="siteTypesiteController">
    <select required
        ng-model="sites.siteesTypeSite"
        name="siteesTypeSite"
        ng-options="typesites as typesites.typeSite for typesites in page.source "
       >
        <option value="">-- Select Type site --</option>
</select><br>

我在浏览器中提交之前有这个：

Object {codeOracle: "test", codeGSM: "test", area: "test", siteesTypeSite: Object}
area: "test"
codeGSM: "test"
codeOracle: "test"
siteesTypeSite: Object
       idTypeSite: 2
       sitees: Array[0]
       typeSite: "Public"
       __proto__: Object
__proto__: Object

typesites.typeSite问题是：如果我将 select 的值更改为而不是typesites这样，我无法提交嵌套对象 

 <div   ng-controller="siteTypesiteController">
<select required
        ng-model="sites.siteesTypeSite"
        name="siteesTypeSite"
        ng-options="typesites.typeSite as typesites.typeSite for typesites in page.source "
       >
        <option value="">-- Select Type site --</option>
</select><br>

提交工作正常，但我有两个插入：表中的插入，以及具有新外键typesite 的表中的插入。site

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