4

我使用 ksoap2 库从 android 客户端与 SOAP Web 服务进行通信。ksoap 团队做得很好，但问题是，没有任何好的例子可以在不同方面正确使用它。例如，我得到以下数据的肥皂响应：

anyType{
    StatusSetting=anyType{Id=1; Name=Til afskrivning; LocationId=1; Editable=true; Default=true; Transcribed=false; }; 
    StatusSetting=anyType{Id=2; Name=Afskrevet; LocationId=1; Editable=false; Default=false; Transcribed=true; }; 
    ...
}

它是一个复杂的对象，或者更确切地说是 StatusSetting 对象的集合。当我尝试获取 SoapObject 的属性时，它只有 1 个属性，所有数据都作为字符串。它也不能被解析为json。令人难以置信的是，没有人遇到过关于 android 越来越受欢迎的问题。知道是否有人解决了这个问题以及如何解决这个问题会很酷。谢谢。

4

5 回答 5

8

例如你的回应：

anyType
{
  FOO_DEALS=anyType
  {
       CATEGORY_LIST=anyType
       {
         CATEGORY=Books; 
         CATEGORY_URL=books_chennai; 
         CATEGORY_ICON=http://deals.foo.com/common/images/books.png; 
         CATEGORY_COUNT=1045; 
         TYPE=1; 
         SUPERTAG=Books; 
       };
       CATEGORY_LIST=anyType
       {
           CATEGORY=Cameras;
           CATEGORY_URL=cameras_chennai;
           CATEGORY_ICON=http://deals.foo.com/common/images/cameras.png; 
           CATEGORY_COUNT=152; 
           SUPERTAG=Cameras; 
           TYPE=1; 
       }; 
   }; 
 }

对于请求和解析，请执行以下操作：

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
           // Add the input required by web service
           request.addProperty("city","chennai");
           request.addProperty("key","10000");

           SoapSerializationEnvelope envelope =new SoapSerializationEnvelope(SoapEnvelope.VER11);
           envelope.setOutputSoapObject(request);

           // Make the soap call.
           androidHttpTransport.call(SOAP_ACTION, envelope);

           // Get the SoapResult from the envelope body.
           resultRequestSOAP = (SoapObject) envelope.bodyIn;


           System.out.println("********Response : "+resultRequestSOAP.toString());

           SoapObject root = (SoapObject) resultRequestSOAP.getProperty(0);
           SoapObject s_deals = (SoapObject) root.getProperty("FOO_DEALS");

           StringBuilder stringBuilder = new StringBuilder();

           System.out.println("********Count : "+ s_deals.getPropertyCount());

           for (int i = 0; i < s_deals.getPropertyCount(); i++) 
           {
               Object property = s_deals.getProperty(i);
               if (property instanceof SoapObject)
               {
                   SoapObject category_list = (SoapObject) property;
                   String CATEGORY = category_list.getProperty("CATEGORY").toString();
                   String CATEGORY_URL = category_list.getProperty("CATEGORY_URL").toString();
                   String CATEGORY_ICON = category_list.getProperty("CATEGORY_ICON").toString();
                   String CATEGORY_COUNT = category_list.getProperty("CATEGORY_COUNT").toString();
                   String SUPERTAG = category_list.getProperty("SUPERTAG").toString();
                   String TYPE = category_list.getProperty("TYPE").toString();
                   stringBuilder.append
                   (
                        "Row value of: " +(i+1)+"\n"+
                        "Category: "+CATEGORY+"\n"+
                        "Category URL: "+CATEGORY_URL+"\n"+
                        "Category_Icon: "+CATEGORY_ICON+"\n"+
                        "Category_Count: "+CATEGORY_COUNT+"\n"+
                        "SuperTag: "+SUPERTAG+"\n"+
                        "Type: "+TYPE+"\n"+
                        "******************************"
                   );                   
                   stringBuilder.append("\n");
               }
           }
于 2012-04-17T07:38:53.297 回答
4 
SoapObject countryDetails = (SoapObject)envelope.getResponse();
System.out.println(countryDetails.toString());

ArrayList list = new ArrayList(countryDetails.getPropertyCount());
lv_arr = new String[countryDetails.getPropertyCount()];
for (int i = 0; i < countryDetails.getPropertyCount(); i++) {
    Object property = countryDetails.getProperty(i);
    if (property instanceof SoapObject) {
        SoapObject countryObj = (SoapObject) property;
        String countryName = countryObj.getProperty("countryName").toString();
        list.add(countryName );
    }
}

希望它应该工作

于 2010-10-29T10:11:02.603 回答
2

这是关于如何使用 KSOAP 处理复杂对象数组的教程。我通过无数小时的调试发现了。希望这能帮助

于 2010-10-25T15:12:39.187 回答
1

我的项目它的工作。希望这有帮助。

        SoapObject requestx = new SoapObject(NAMESPACE, METHOD_NAME);

        SoapSerializationEnvelope envelopex = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelopex.dotNet = true;
        envelopex.setOutputSoapObject(requestx);
        HttpTransportSE httpTransportx = new HttpTransportSE(URL);          

        try  {                    
            httpTransportx.call(SOAP_ACTION, envelopex);
            SoapObject responsex = (SoapObject)envelopex.getResponse(); // not envelopex.bodyIn;

             int i=0;
             int RCount=responsex.getPropertyCount();
             int[] tbIDArray = new int[RCount+1];
             int[] iMonthAarray = new int[RCount+1];
             int[] iYearAarray = new int[RCount+1];
             String[] sDetailAarray = new String[RCount+1];

             for (i = 0; i < RCount; i++) {
                 Object property = responsex.getProperty(i);
                 if (property instanceof SoapObject) {
                     SoapObject info = (SoapObject) property;
                     String tbID = info.getProperty("tbID").toString();
                     String iMonth = info.getProperty("iMonth").toString();
                     String iYear = info.getProperty("iYear").toString();
                     String sDetail = info.getProperty("sDetail").toString();

                    tbIDArray[i] =Integer.valueOf(tbID);
                    iMonthAarray[i] =Integer.valueOf(iMonth);
                    iYearAarray[i] =Integer.valueOf(iYear);
                    sDetailAarray[i] =sDetail;
                 }//if (property instanceof SoapObject) {
             }//for (i = 0; i < RCount; i++) {


        }  catch (Exception exception)   {
            MsgBox1(exception.toString() , "Error");
        }
于 2013-03-31T19:47:26.287 回答
0

JSON 格式很舒服。我编写了一个简单的代码来将 SOAP V1 响应转换为 JSON：

public static String soapStrToJson(String input)
{
    String output;

    output = input;
    output = output.replace("key=", "\"");
    output = output.replace("; value=", "\":");
    output = output.replace("; };",",");
    output = output.replace("item=anyType{","");
    output = output.replace("Map","");
    output = output.replace(",}","}");
    output = output.replace(", }"," }");
    output = output.replace("null","0");

    Pattern pattern = Pattern.compile(":(.*?),");
    Matcher matcher = pattern.matcher(output);

    List<String> wordsToReplace = new ArrayList();
    while (matcher.find())
    {
        String str = matcher.group(0);
        if(str.contains("{") || str.contains("["))
            continue;

        str = str.replace(":", "");
        str = str.replace(",", "");

        if(str.matches("^-?\\d+$"))
            continue;

        System.out.println("-->" + str);
        wordsToReplace.add(str);
    }

    for(String str : wordsToReplace)
    {
        output = output.replace(":"+str+",", ":\""+str+"\",");
    }
    return output;
}

并将此功能用作：

parseCategoryJSON( new JSONObject( soapStrToJson( env.getResponse().toString() ) ) )

请注意，我没有使用env.bodyIn SoapObject。

这可能不是所有响应的完美转换器，因此请根据您的要求修改“String.replace”和 Pattern-Matchers。

于 2016-01-19T15:40:13.210 回答