1

对于我的项目，我需要多个对话框相互链接。一个按钮将进入一级，另一个按钮将返回两级。为了在不显示所有代码的情况下大致了解我正在寻找的内容，这是一个可编译的示例：

'''
Created on 2010-06-18

@author: dhatt
'''

import sys
from PyQt4 import QtGui, QtCore

class WindowLV3(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV3')

        quit = QtGui.QPushButton('Close', self)
        quit.setGeometry(10, 10, 60, 35)

        self.connect(quit, QtCore.SIGNAL('clicked()'),
            QtGui.qApp, QtCore.SLOT('quit()'))  # this will close entire program


class WindowLV2(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.Window3 = WindowLV3()

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV2')

        quit = QtGui.QPushButton('Close', self)
        quit.setGeometry(10, 10, 60, 35)

        next = QtGui.QPushButton('Lv3', self)
        next.setGeometry(10, 50, 60, 35)

        self.connect(quit, QtCore.SIGNAL('clicked()'),
            QtGui.qApp, QtCore.SLOT('reject()'))  # this doesn't work

        self.connect(next, QtCore.SIGNAL('clicked()'),
            self.nextWindow)

    def nextWindow(self):
        self.Window3.show()


class WindowLV1(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.Window2 = WindowLV2()

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV1')

        next = QtGui.QPushButton('Lv2', self)
        next.setGeometry(10, 50, 60, 35)

        quit = QtGui.QPushButton('Close', self)
        quit.setGeometry(10, 10, 60, 35)

        self.connect(next, QtCore.SIGNAL('clicked()'),
            self.nextWindow)

    def nextWindow(self):
        self.Window2.show()

        self.connect(quit, QtCore.SIGNAL('clicked()'),
            QtGui.qApp, QtCore.SLOT('reject()'))  # this doesn't work        


if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)
    Window1 = WindowLV1()
    Window1.show()
    sys.exit(app.exec_())

问题是我无法从窗口关闭并显示上一个窗口。例如，如果我从 LV3 窗口中单击“关闭”按钮，它会将控制权转移回 LV2 窗口。我可以调用 QtCore.SLOT('quit()'))，但它会关闭整个程序，我不希望这样。

我在这里做错了什么？

4

1 回答 1

1

这里有两件事需要解决。

  1. 您可以简单地在 connect 方法中调用 QDialog.close 。

  2. 在def nextWindow(self):您尝试连接局部变量退出时。所以它不会工作。您需要将退出定义为实例变量（self.quit）

    self.connect(self.quit, QtCore.SIGNAL('clicked()'), self.close) # 这应该可以

这是修改后的代码：

import sys
from PyQt4 import QtGui, QtCore

class WindowLV3(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV3')

        self.quit = QtGui.QPushButton('Close', self)
        self.quit.setGeometry(10, 10, 60, 35)

        self.connect(self.quit, QtCore.SIGNAL('clicked()'),
            self.close)  # this will close entire program


class WindowLV2(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.Window3 = WindowLV3()

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV2')

        self.quit = QtGui.QPushButton('Close', self)
        self.quit.setGeometry(10, 10, 60, 35)

        next = QtGui.QPushButton('Lv3', self)
        next.setGeometry(10, 50, 60, 35)

        self.connect(self.quit, QtCore.SIGNAL('clicked()'),
            self.close)  # this should work

        self.connect(next, QtCore.SIGNAL('clicked()'),
            self.nextWindow)

    def nextWindow(self):
        self.Window3.show()


class WindowLV1(QtGui.QDialog):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.Window2 = WindowLV2()

        self.setGeometry(300, 300, 120, 150)
        self.setWindowTitle('LV1')

        next = QtGui.QPushButton('Lv2', self)
        next.setGeometry(10, 50, 60, 35)

        self.quit = QtGui.QPushButton('Close', self)
        self.quit.setGeometry(10, 10, 60, 35)

        self.connect(next, QtCore.SIGNAL('clicked()'),
            self.nextWindow)

    def nextWindow(self):
        self.Window2.show()

        self.connect(self.quit, QtCore.SIGNAL('clicked()'),
            self.close)  # this should work        


if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)
    Window1 = WindowLV1()
    Window1.show()
    sys.exit(app.exec_())
于 2010-06-19T06:47:48.753 回答