我想将某个设置Drawable为设备的壁纸，但所有壁纸功能Bitmap都只接受 s。我不能使用WallpaperManager，因为我是 2.1 之前的版本。
此外，我的可绘制对象是从网上下载的，而不是驻留在R.drawable.
问问题
745501 次
21 回答
1365
这段代码有帮助。
Bitmap icon = BitmapFactory.decodeResource(context.getResources(),
R.drawable.icon_resource);
这是下载图像的版本。
String name = c.getString(str_url);
URL url_value = new URL(name);
ImageView profile = (ImageView)v.findViewById(R.id.vdo_icon);
if (profile != null) {
Bitmap mIcon1 =
BitmapFactory.decodeStream(url_value.openConnection().getInputStream());
profile.setImageBitmap(mIcon1);
}
于 2010-06-14T08:32:47.823 回答
804
public static Bitmap drawableToBitmap (Drawable drawable) {
Bitmap bitmap = null;
if (drawable instanceof BitmapDrawable) {
BitmapDrawable bitmapDrawable = (BitmapDrawable) drawable;
if(bitmapDrawable.getBitmap() != null) {
return bitmapDrawable.getBitmap();
}
}
if(drawable.getIntrinsicWidth() <= 0 || drawable.getIntrinsicHeight() <= 0) {
bitmap = Bitmap.createBitmap(1, 1, Bitmap.Config.ARGB_8888); // Single color bitmap will be created of 1x1 pixel
} else {
bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
}
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
于 2012-05-15T12:33:19.967 回答
217
这会将 BitmapDrawable 转换为 Bitmap。
Drawable d = ImagesArrayList.get(0);
Bitmap bitmap = ((BitmapDrawable)d).getBitmap();
于 2010-06-14T09:33:55.730 回答
151
ADrawable可以绘制到 a 上Canvas，并且 aCanvas可以由 a 支持Bitmap：
（更新以处理BitmapDrawables 的快速转换并确保Bitmap创建的大小有效）
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
int width = drawable.getIntrinsicWidth();
width = width > 0 ? width : 1;
int height = drawable.getIntrinsicHeight();
height = height > 0 ? height : 1;
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
于 2012-02-22T07:35:43.647 回答
58
方法1：您可以像这样直接转换为位图
Bitmap myLogo = BitmapFactory.decodeResource(context.getResources(), R.drawable.my_drawable);
方法 2：您甚至可以将资源转换为可绘制对象，并从中获得像这样的位图
Bitmap myLogo = ((BitmapDrawable)getResources().getDrawable(R.drawable.logo)).getBitmap();
对于API > 22 getDrawable方法移动到ResourcesCompat类所以你做这样的事情
Bitmap myLogo = ((BitmapDrawable) ResourcesCompat.getDrawable(context.getResources(), R.drawable.logo, null)).getBitmap();
于 2018-02-02T05:22:48.940 回答
40
1）可绘制到位图：
Bitmap mIcon = BitmapFactory.decodeResource(context.getResources(),R.drawable.icon);
// mImageView.setImageBitmap(mIcon);
2）位图到可绘制：
Drawable mDrawable = new BitmapDrawable(getResources(), bitmap);
// mImageView.setDrawable(mDrawable);
于 2019-11-07T07:23:38.977 回答
39
android-ktx 有Drawable.toBitmap方法：https ://android.github.io/android-ktx/core-ktx/androidx.graphics.drawable/android.graphics.drawable.-drawable/to-bitmap.html
来自科特林
val bitmap = myDrawable.toBitmap()
于 2019-06-05T16:41:47.423 回答
32
很简单
Bitmap tempBMP = BitmapFactory.decodeResource(getResources(),R.drawable.image);
于 2013-03-21T18:21:30.080 回答
18
最新的 androidx 核心库 (androidx.core:core-ktx:1.2.0) 现在有一个扩展功能：Drawable.toBitmap(...)将 Drawable 转换为 Bitmap。
于 2020-03-12T05:48:25.107 回答
16
因此，在查看（和使用）其他答案之后，似乎他们都处理ColorDrawable得PaintDrawable不好。（特别是在棒棒糖上）似乎对Shaders 进行了调整，因此无法正确处理纯色块。
我现在正在使用以下代码：
public static Bitmap drawableToBitmap(Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable) drawable).getBitmap();
}
// We ask for the bounds if they have been set as they would be most
// correct, then we check we are > 0
final int width = !drawable.getBounds().isEmpty() ?
drawable.getBounds().width() : drawable.getIntrinsicWidth();
final int height = !drawable.getBounds().isEmpty() ?
drawable.getBounds().height() : drawable.getIntrinsicHeight();
// Now we check we are > 0
final Bitmap bitmap = Bitmap.createBitmap(width <= 0 ? 1 : width, height <= 0 ? 1 : height,
Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
与其他人不同的是，如果您在要求将其转换为位图之前调用setBounds它Drawable，它将以正确的大小绘制位图！
于 2014-12-18T09:54:24.360 回答
13
也许这会帮助某人......
从 PictureDrawable 到 Bitmap，使用：
private Bitmap pictureDrawableToBitmap(PictureDrawable pictureDrawable){
Bitmap bmp = Bitmap.createBitmap(pictureDrawable.getIntrinsicWidth(), pictureDrawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bmp);
canvas.drawPicture(pictureDrawable.getPicture());
return bmp;
}
...这样实施：
Bitmap bmp = pictureDrawableToBitmap((PictureDrawable) drawable);
于 2012-02-08T19:08:03.707 回答
12
这里有更好的分辨率
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static InputStream bitmapToInputStream(Bitmap bitmap) {
int size = bitmap.getHeight() * bitmap.getRowBytes();
ByteBuffer buffer = ByteBuffer.allocate(size);
bitmap.copyPixelsToBuffer(buffer);
return new ByteArrayInputStream(buffer.array());
}
于 2013-10-22T11:56:05.840 回答
12
这是@Chris.Jenkins在这里提供的答案的不错的Kotlin版本：https ://stackoverflow.com/a/27543712/1016462
fun Drawable.toBitmap(): Bitmap {
if (this is BitmapDrawable) {
return bitmap
}
val width = if (bounds.isEmpty) intrinsicWidth else bounds.width()
val height = if (bounds.isEmpty) intrinsicHeight else bounds.height()
return Bitmap.createBitmap(width.nonZero(), height.nonZero(), Bitmap.Config.ARGB_8888).also {
val canvas = Canvas(it)
setBounds(0, 0, canvas.width, canvas.height)
draw(canvas)
}
}
private fun Int.nonZero() = if (this <= 0) 1 else this
于 2017-12-29T21:06:52.207 回答
9
位图位图 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon);
这不会每次都起作用，例如，如果您的可绘制对象是可绘制的图层列表，那么它会给出空响应，因此作为替代方案，您需要将可绘制对象绘制到画布中然后保存为位图，请参阅下面的一段代码。
public void drawableToBitMap(Context context, int drawable, int widthPixels, int heightPixels) {
try {
File file = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + "/", "drawable.png");
FileOutputStream fOut = new FileOutputStream(file);
Drawable drw = ResourcesCompat.getDrawable(context.getResources(), drawable, null);
if (drw != null) {
convertToBitmap(drw, widthPixels, heightPixels).compress(Bitmap.CompressFormat.PNG, 100, fOut);
}
fOut.flush();
fOut.close();
} catch (Exception e) {
e.printStackTrace();
}
}
private Bitmap convertToBitmap(Drawable drawable, int widthPixels, int heightPixels) {
Bitmap bitmap = Bitmap.createBitmap(widthPixels, heightPixels, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, widthPixels, heightPixels);
drawable.draw(canvas);
return bitmap;
}
上面的代码将你在下载目录中的drawable保存为drawable.png
于 2020-06-21T10:10:29.607 回答
8
Android 提供了一个非直接的解决方案：BitmapDrawable. 要获取 Bitmap ，我们必须将资源 id 提供R.drawable.flower_pic给 a BitmapDrawable，然后将其转换为 a Bitmap。
Bitmap bm = ((BitmapDrawable) getResources().getDrawable(R.drawable.flower_pic)).getBitmap();
于 2014-05-29T01:39:04.980 回答
5
使用此代码。它将帮助您实现目标。
Bitmap bmp=BitmapFactory.decodeResource(getResources(), R.drawable.profileimage);
if (bmp!=null) {
Bitmap bitmap_round=getRoundedShape(bmp);
if (bitmap_round!=null) {
profileimage.setImageBitmap(bitmap_round);
}
}
public Bitmap getRoundedShape(Bitmap scaleBitmapImage) {
int targetWidth = 100;
int targetHeight = 100;
Bitmap targetBitmap = Bitmap.createBitmap(targetWidth,
targetHeight,Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(targetBitmap);
Path path = new Path();
path.addCircle(((float) targetWidth - 1) / 2,
((float) targetHeight - 1) / 2,
(Math.min(((float) targetWidth),
((float) targetHeight)) / 2),
Path.Direction.CCW);
canvas.clipPath(path);
Bitmap sourceBitmap = scaleBitmapImage;
canvas.drawBitmap(sourceBitmap,
new Rect(0, 0, sourceBitmap.getWidth(),
sourceBitmap.getHeight()),
new Rect(0, 0, targetWidth, targetHeight), new Paint(Paint.FILTER_BITMAP_FLAG));
return targetBitmap;
}
于 2014-05-30T12:13:47.197 回答
5
BitmapFactory.decodeResource()自动缩放位图，因此您的位图可能会变得模糊。要防止缩放，请执行以下操作：
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
或者
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);
于 2019-07-09T00:06:19.107 回答
2
ImageWorker 库可以将位图转换为可绘制或 base64，反之亦然。
val bitmap: Bitmap? = ImageWorker.convert().drawableToBitmap(sourceDrawable)
执行
在项目级别 Gradle
allprojects {
repositories {
...
maven { url 'https://jitpack.io' }
}
}
在应用程序级别 Gradle
dependencies {
implementation 'com.github.1AboveAll:ImageWorker:0.51'
}
您还可以从外部存储和检索位图/drawables/base64 图像。
在这里检查。https://github.com/1AboveAll/ImageWorker/edit/master/README.md
于 2018-12-09T04:52:58.053 回答
2
如果您使用的是 kotlin，请使用以下代码。它会工作的
// 用于使用图像路径
val image = Drawable.createFromPath(path)
val bitmap = (image as BitmapDrawable).bitmap
于 2019-07-19T08:08:12.343 回答
1
// get image path from gallery
protected void onActivityResult(int requestCode, int resultcode, Intent intent) {
super.onActivityResult(requestCode, resultcode, intent);
if (requestCode == 1) {
if (intent != null && resultcode == RESULT_OK) {
Uri selectedImage = intent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
//display image using BitmapFactory
cursor.close(); bmp = BitmapFactory.decodeFile(filepath);
iv.setBackgroundResource(0);
iv.setImageBitmap(bmp);
}
}
}
于 2012-12-21T04:21:43.610 回答
0
我在这个线程上使用了一些答案，但其中一些没有按预期工作（也许他们在旧版本中工作过）但我想在几次尝试和错误后分享我的，使用扩展功能：
val markerOption = MarkerOptions().apply {
position(LatLng(driver.lat, driver.lng))
icon(R.drawabel.your_drawable.toBitmapDescriptor(context))
snippet(driver.driverId.toString())
}
mMap.addMarker(markerOption)
这是扩展功能：
fun Int.toBitmapDescriptor(context: Context): BitmapDescriptor {
val vectorDrawable = ResourcesCompat.getDrawable(context.resources, this, context.theme)
val bitmap = vectorDrawable?.toBitmap(
vectorDrawable.intrinsicWidth,
vectorDrawable.intrinsicHeight,
Bitmap.Config.ARGB_8888
)
return BitmapDescriptorFactory.fromBitmap(bitmap!!)
}
于 2022-01-27T01:06:03.017 回答