3

我目前拥有的代码:

<?php

  /** PHPExcel */
  require_once '../Classes/PHPExcel.php';

  /** PHPExcel_IOFactory */
  require_once '../Classes/PHPExcel/IOFactory.php';

  // Create new PHPExcel object
  $objPHPExcel = new PHPExcel();

  // Set properties
  $objPHPExcel->getProperties()->setCreator("Maarten Balliauw")
                               ->setLastModifiedBy("Maarten Balliauw")
                               ->setTitle("Office 2007 XLSX Test Document")
                               ->setSubject("Office 2007 XLSX Test Document")
                               ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.")
                               ->setKeywords("office 2007 openxml php")
                               ->setCategory("Test result file");

  $result = 'select * from table1';

  for($i=0;$i<count($result);$i++) {

    $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id'];

    for ($j=0;$j<count($result1);$j++) {
      $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']);
    }

    // Set active sheet index to the first sheet, so Excel opens this as the first sheet
    $objPHPExcel->setActiveSheetIndex(0);

    // Save Excel 2007 file
    $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007');
    $objWriter->save(str_replace('.php', '.xlsx', __FILE__));

    // Echo done
    echo date('H:i:s') . " Done writing file.\r\n";       
  }

?>

上面的代码执行并.xlsx在文件夹中保存 n 个文件,但我遇到的问题是在所有保存的 excel 文件中执行count(result1)for循环中最大的问题。

4

2 回答 2

3

在深入之前,有一件事很清楚

您还没有执行 $result 的查询,也没有获取它,并且在 $result1 查询中您正在使用它,这是不可能的,

$result1 也存在同样的问题

您可以使用:

$result = mysql_query('select * from table1');
while($fetch_result=mysql_fetch_array($result))
{
    $result2 = mysql("select * from table2 where table1_id = '".$fetch_result['table1_id']."'");

   while($fetch_result2=mysql_fetch_array($result2)
   {
    --your code--

但是最好写 JOIN 而不是这两个查询

于 2010-06-11T13:16:12.590 回答
0

你会想要mysql_num_rows- http://php.net/manual/en/function.mysql-num-rows.php

$q = 'select * from table1';
$res = mysql_query($q);
$count = mysql_num_rows($result);

for ($j=0;$j<$count;$j++) {
    #code here
}

你可能还想看看mysql_fetch_assoc

于 2010-06-11T13:07:24.523 回答