1

I define a type called inputTy using std::array (c++11) , the dimension of the array declared as an external constant integer d.

namespace project {
  namespace types{
    extern const int d;
    typedef std::array<double, d> inputTy;
  }
}

Why do I get such compilation error?

../../include/types.h:16:29: error: the value of ‘d’ is not usable in a constant expression
 typedef std::array<double, d> inputTy;
                             ^
../../include/types.h:15:18: note: ‘d’ was not initialized with a constant expression
 extern const int d;
              ^

Thanks for your help.

4

1 回答 1

3

You can not use extern const int as array size because compiler does not know the size of a constant from other compilation unit.

Change your design to use std::vector or some other container to overcome the problem or put the constant in a header and include it before typedefing.

于 2015-05-13T13:38:50.983 回答