您如何创建一个仅以货币格式格式化输入的edittext条目?当用户输入 5 时,我希望输入看起来像“$0.05”,然后当他们输入 3 时,输入现在应该看起来像“$0.53”,最后他们输入 6,输入应该看起来像“$5.36”。
问问题
10736 次
7 回答
8
ninjasense 的完整解决方案基本上可以工作,但它有一些问题:
- 每次在“onTextChanged”处理程序中更改字段的数据时,光标位置都会重置为字段上的索引 0,这在键入货币值时会发生一些烦人的情况。
- 它使用浮点数来格式化货币值,这可能会适得其反。
对于第一个问题我还没有解决方案,对于第二个这样的代码有效:
@Override
public void onTextChanged(CharSequence s, int start,
int before, int count) {
if(!s.toString().matches("^\\$(\\d{1,3}(\\,\\d{3})*|(\\d+))(\\.\\d{2})?$"))
{
String userInput= ""+s.toString().replaceAll("[^\\d]", "");
StringBuilder cashAmountBuilder = new StringBuilder(userInput);
while (cashAmountBuilder.length() > 3 && cashAmountBuilder.charAt(0) == '0') {
cashAmountBuilder.deleteCharAt(0);
}
while (cashAmountBuilder.length() < 3) {
cashAmountBuilder.insert(0, '0');
}
cashAmountBuilder.insert(cashAmountBuilder.length()-2, '.');
cashAmountBuilder.insert(0, '$');
cashAmountEdit.setText(cashAmountBuilder.toString());
}
}
于 2011-03-04T09:23:49.587 回答
3
建立 Zds。
为了将光标保持在字段的末尾,请使用它。
cashAmountEdit.setTextKeepState(cashAmountBuilder.toString());
Selection.setSelection(cashAmountEdit.getText(), cashAmountBuilder.toString().length());
于 2011-03-23T22:13:12.510 回答
1
我发现 TextWatcher 有点麻烦。相反,您可以设置密钥侦听器:
setKeyListener(new CalculatorKeyListener());
// Must be called after setKeyListener(), otherwise is overridden
setRawInputType(Configuration.KEYBOARD_12KEY);
然后创建一个扩展 NumberKeyListener 的 KeyListener:
class CalculatorKeyListener extends NumberKeyListener {
@Override
public int getInputType() {
return InputType.TYPE_CLASS_NUMBER;
}
@Override
public boolean onKeyDown(View view, Editable content, int keyCode, KeyEvent event) {
if (keyCode >= KeyEvent.KEYCODE_0 && keyCode <= KeyEvent.KEYCODE_9) {
digitPressed(keyCode - KeyEvent.KEYCODE_0);
} else if (keyCode == KeyEvent.KEYCODE_DEL) {
deletePressed();
}
return true;
}
@Override
protected char[] getAcceptedChars() {
return new char[] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
}
}
然后您需要正确显示字符,但这并不难;只需跟踪美分,然后除以或乘以 10,并使用 NumberFormat 来获得正确的格式。
于 2010-12-30T16:49:26.290 回答
1
您可以使用 TextWatcher 来执行此类操作。
扩展 TextWatcher:http ://d.android.com/reference/android/text/TextWatcher.html
public class MyTextWatcher implements TextWatcher {
public void afterTextChanged(Editable arg0) {
}
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
}
然后将其添加到您的editText
myEditText.addTextChangedListener(new MyTextWatcher());
于 2010-06-10T11:26:38.000 回答
1
这是我的完整解决方案:
tvValue.setRawInputType(Configuration.KEYBOARD_12KEY);
tvValue.addTextChangedListener(new TextWatcher(){
@Override
public void afterTextChanged(Editable arg0) {
// TODO Auto-generated method stub
}
@Override
public void beforeTextChanged(CharSequence s, int start,
int count, int after) {
// TODO Auto-generated method stub
}
@Override
public void onTextChanged(CharSequence s, int start,
int before, int count) {
// TODO Auto-generated method stub
// here i converted to string
if(!s.toString().matches("^\\$(\\d{1,3}(\\,\\d{3})*|(\\d+))(\\.\\d{2})?$"))
{
String userInput= ""+s.toString().replaceAll("[^\\d]", "");
Float in=Float.parseFloat(userInput);
float percen = in/100;
tvValue.setText("$"+percen);
}
}
});
于 2011-02-21T21:20:36.263 回答
0
我这样做了,但没有小数点,用点表示英里,检查代码并添加支持小数点的功能。
MyEditText.addTextChangedListener(new TextWatcher()
{
@Override
public void onTextChanged(CharSequence s, int start, int before, int count){
if(s.toString().length() > 0){
MyEditText.removeTextChangedListener(this);
String numbers = removeCharacters(s.toString());
int money = 0;
try{
money = Integer.parseInt(numbers);
}
catch(Exception ex){
money = 0;
}
MyEditText.setText(getMoney(money));
//Set cursor on correct position
int selection = start;
if(count > 0){
selection++;
if(MyEditText.getText().toString().length() == 2 || MyEditText.getText().toString().length() == 6 || MyEditText.getText().toString().length() == 10){
selection++;
}
}
else{
if(MyEditText.getText().toString().length() == 4 || MyEditText.getText().toString().length() == 8){
selection--;
}
}
if(selection > MyEditText.getText().toString().length()){
selection = MyEditText.getText().toString().length();
}
MyEditText.setSelection(selection);
MyEditText.addTextChangedListener(this);
}
if(s.toString().length() == 1 && count < 1 && start == 1){
MyEditText.removeTextChangedListener(this);
MyEditText.setText("");
MyEditText.addTextChangedListener(this);
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after){
}
@Override
public void afterTextChanged(Editable s)
{
}
});
public String removeCharacters(String money){
int i=0;
while (i<money.length())
{
Character c = money.charAt(i);
if (Character.isDigit(c) && c != '.')
{
i++;
}
else
{
money = money.replace(c.toString(), "");
}
}
return money;
}
public String getMoney(int value){
String money = "$";
NumberFormat numberFormatter;
numberFormatter = NumberFormat.getNumberInstance(Locale.GERMAN);
money += numberFormatter.format(value);
return money;
}
于 2013-12-19T21:05:22.530 回答
0
此答案基于Zds 的答案(这又基于ninjasense 的答案),但这应该可以解决光标位置问题:
if(!text.matches("^\\$(\\d{1,2})(\\.\\d{2})?$")) {
int originalCursorPosition = view.getSelectionStart();
int cursorOffset = 0;
boolean cursorAtEnd = originalCursorPosition == text.length();
String userInput= ""+text.replaceAll("[^\\d]", "");
StringBuilder cashAmountBuilder = new StringBuilder(userInput);
while (cashAmountBuilder.length() > 3 && cashAmountBuilder.charAt(0) == '0') {
cashAmountBuilder.deleteCharAt(0);
cursorOffset--;
}
while (cashAmountBuilder.length() < 3) {
cashAmountBuilder.insert(0, '0');
cursorOffset++;
}
cashAmountBuilder.insert(cashAmountBuilder.length() - 2, '.');
cashAmountBuilder.insert(0, '$');
view.setText(cashAmountBuilder.toString());
view.setSelection(cursorAtEnd ? view.getText().length() : originalCursorPosition + cursorOffset);
}
笔记:
- 以下是在一个
TextWatcher.onTextChanged
- 我使用的正则表达式与其他答案不同,这使价格保持在 < 100 美元
- 'view' 是编辑文本,'text' 是字符串内容
- 这对我使用
EditText
amaxLength
为 6(即 00.00 美元)有效
于 2015-08-05T08:03:56.583 回答