所以我刚刚修复了以下代码中的一个有趣的错误,但我不确定我采用的最佳方法:
p = 1
probabilities = [ ... ] # a (possibly) long list of numbers between 0 and 1
for wp in probabilities:
if (wp > 0):
p *= wp
# Take the natural log, this crashes when 'probabilites' is long enough that p ends up
# being zero
try:
result = math.log(p)
因为结果不需要精确,我通过简单地保持最小的非零值来解决这个问题,如果 p 变成 0 就使用它。
p = 1
probabilities = [ ... ] # a long list of numbers between 0 and 1
for wp in probabilities:
if (wp > 0):
old_p = p
p *= wp
if p == 0:
# we've gotten so small, its just 0, so go back to the smallest
# non-zero we had
p = old_p
break
# Take the natural log, this crashes when 'probabilites' is long enough that p ends up
# being zero
try:
result = math.log(p)
这行得通,但对我来说似乎有点笨拙。我不做大量这种数值编程,我不确定这是否是人们使用的那种修复方法,或者是否有更好的东西我可以去做。