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我正在尝试为 xml 回发侦听器编写解析器，但似乎无法让它转储 xml 以获取示例。API 支持人员告诉我使用“DOMDocument”，也许是“SimpleXML”？无论如何，这是代码：（谢谢！）

<?php
$xml_document = file_get_contents('php://input');
$doc = new DOMDocument();
$doc->loadXML($xml_document);
$doc->save("test2/".time().".sample.xml").".xml");
?>
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1 回答 1

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用它来创建一个 XML 文件怎么样？

/**
 * Will output in a similar form to print_r, but the nodes are xml so can be collapsed in browsers
 *
 * @param mixed $mixed
 */
function print_r_xml($mixed)
{
    // capture the output of print_r
    $out = print_r($mixed, true);

    // Replace the root item with a struct
    // MATCH : '<start>element<newline> ('
    $root_pattern = '/[ \t]*([a-z0-9 \t_]+)\n[ \t]*\(/i';
    $root_replace_pattern = '<struct name="root" type="\\1">';
    $out = preg_replace($root_pattern, $root_replace_pattern, $out, 1);

    // Replace array and object items structs
    // MATCH : '[element] => <newline> ('
    $struct_pattern = '/[ \t]*\[([^\]]+)\][ \t]*\=\>[ \t]*([a-z0-9 \t_]+)\n[ \t]*\(/miU';
    $struct_replace_pattern = '<struct name="\\1" type="\\2">';
    $out = preg_replace($struct_pattern, $struct_replace_pattern, $out);
    // replace ')' on its own on a new line (surrounded by whitespace is ok) with '</var>
    $out = preg_replace('/^\s*\)\s*$/m', '</struct>', $out);

    // Replace simple key=>values with vars
    // MATCH : '[element] => value<newline>'
    $var_pattern = '/[ \t]*\[([^\]]+)\][ \t]*\=\>[ \t]*([a-z0-9 \t_\S]+)/i';
    $var_replace_pattern = '<var name="\\1">\\2</var>';
    $out = preg_replace($var_pattern, $var_replace_pattern, $out);

    $out =  trim($out);
    $out='<?xml version="1.0"?><data>'.$out.'</data>';

    return $out;
}

我在我的应用程序中发布了所有 $_POST 变量：

$handle = fopen("data.xml", "w+");
$content = print_r_xml($_POST);
fwrite($handle,$content);
fclose();
于 2010-06-08T03:56:05.413 回答