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下面的代码是数字猜谜游戏的一部分，其中计算机在用户指定的范围内生成一个随机数。在这里，我试图将用户限制为 10 次猜测。如果他/她超过 10，则游戏结束：

int t1 = 0;//stores # of guesses

while(true){//loop begins
t1++;//increments each iteration to represent # of guesses 

if(g1!=n){//if the guess is incorrect... (n = # user is trying to guess)

if(t1>10){//# of guesses cannot exceed 10
System.out.println("\nGAME OVER\nYou have exceeded the max # of tries!");
break;}//game ends if user exceeds max # of attempts

if(g1<n){System.out.println("\nGuess Higher!\n" + t1 + "attempt(s) so far");
continue;}//guess is too low    

if(g1>n){System.out.println("\nGuess Lower!\n" + t1 + " attempt(s) so far");
continue;}}//guess is too high (loop ends)

我收到的输出只有 1/2 正确。例如，假设计算机生成了 1-100 范围内的数字 12。在用户第 10 次（最后一次）猜测时，它将打印：“GAME OVER...”；但是，如果用户的猜测太低或太高，它也会打印出来，这是我不想要的。

我要进行哪些更改来纠正此错误？我认为这与嵌套 if 中的“break”语句有关。

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1 回答 1

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你的问题似乎有效。代码是正确的，它正在做它应该做的事情。但是，编写相同代码的更好和更有效的方法是：

// run a for loop that will let user guess 10 times
for (int i = 0; i < 10; i++)
{
    // see if the guessed number is incorrect
    if (g1 != n)
    {
         // check whats wrong with the number entered

         // number of guesses cannot exceed 10
         if ((i+1) >= 10)
         {
             System.out.println("\nGAME OVER\nYou have exceeded the max # of tries!"); 
         }
         else if (g1 < n)
         {
             // if user's guess is less than the number
             System.out.println("\nGuess Higher!\n" + (i+1) + "attempt(s) so far"); 
         }
         else if (g1 > n)
         {
             // if user's guess is greater than the number
             System.out.println("\nGuess Lower!\n" + (i+1) + " attempt(s) so far");
         } 
    } 
} // for loop ends
于 2015-04-14T01:17:20.417 回答