0

我想从二进制（.bin）文件中读取一组 256 个字节并将其存储到缓冲区中。然后我想将这些字节中的每一个移动到一个 char 向量的向量中。另外，我想读取向量中的 char 值并获取该字节二进制值的相应整数值。这就是我的处理方式：

typedef unsigned char BYTE;
vector< vector<BYTE> > pMem (256, vector<BYTE> (256, '0'));
ifstream binStream;
binStream.open("BACKING_STORE.bin", ios::binary | ios::in );
// allocate memory:
char * buffer = new char [256];

binStream.seekg(0, binStream.beg);
binStream.read(buffer, 256);

for( i = 0; i < 256; i++ )
    pMem[0][i] = buffer[i];

for( i = 0; i < 256; i++ )
{
    cout << "Physical memory char contents at 0[" << i << "]: " << pMem[0][i] << endl;
    int x = pMem[0][i];
    cout << "Physical memory integer contents at 0[" << i << "]: " << x << endl;
}

但是当我打印出这些值时，我得到的结果如下：

Physical memory char contents at 0[237]: 
Physical memory integer contents at 0[237]: 0
Physical memory char contents at 0[238]: 
Physical memory integer contents at 0[238]: 0
Physical memory char contents at 0[239]: ;
Physical memory integer contents at 0[239]: 59
Physical memory char contents at 0[240]: 
Physical memory integer contents at 0[240]: 0
Physical memory char contents at 0[241]: 
Physical memory integer contents at 0[241]: 0
Physical memory char contents at 0[242]: 
Physical memory integer contents at 0[242]: 0
Physical memory char contents at 0[243]: <
Physical memory integer contents at 0[243]: 60
Physical memory char contents at 0[244]: 
Physical memory integer contents at 0[244]: 0
Physical memory char contents at 0[245]: 
Physical memory integer contents at 0[245]: 0
Physical memory char contents at 0[246]: 
Physical memory integer contents at 0[246]: 0
Physical memory char contents at 0[247]: =
Physical memory integer contents at 0[247]: 61
Physical memory char contents at 0[248]: 
Physical memory integer contents at 0[248]: 0
Physical memory char contents at 0[249]: 
Physical memory integer contents at 0[249]: 0
Physical memory char contents at 0[250]: 
Physical memory integer contents at 0[250]: 0
Physical memory char contents at 0[251]: >
Physical memory integer contents at 0[251]: 62
Physical memory char contents at 0[252]: 
Physical memory integer contents at 0[252]: 0
Physical memory char contents at 0[253]: 
Physical memory integer contents at 0[253]: 0
Physical memory char contents at 0[254]: 
Physical memory integer contents at 0[254]: 0
Physical memory char contents at 0[255]: ?
Physical memory integer contents at 0[255]: 63

这显然是错误的输出。有人可以解释一下我做错了什么以及如何完成这件事吗？

4

1 回答 1

1

当你有：

char c = 'a';
std::cout << c << std::endl;

输出将是

a

当 的值c对应于非打印字符之一时，输出因系统而异。在你的情况下，你得到空白输出。

如果要'a'打印 的整数表示，则必须对其进行强制转换。

std::cout << (int)c << std::endl;

或者

int x = c;
std::cout << x << std::endl;

我希望这就是您需要的所有解释。

于 2015-04-11T04:20:34.517 回答