75

我需要测试一个需要使用 urllib.urlopen 查询外部服务器上的页面的函数(它也使用 urllib.urlencode)。服务器可能已关闭,页面可能会更改;我不能依靠它进行测试。

控制 urllib.urlopen 返回的最佳方法是什么?

4

8 回答 8

101

另一种简单的方法是让您的测试覆盖 urllib 的urlopen()函数。例如,如果您的模块有

import urllib

def some_function_that_uses_urllib():
    ...
    urllib.urlopen()
    ...

你可以这样定义你的测试:

import mymodule

def dummy_urlopen(url):
    ...

mymodule.urllib.urlopen = dummy_urlopen

然后,当您的测试调用 , 中的函数时mymoduledummy_urlopen()将调用而不是真正的urlopen(). 像 Python 这样的动态语言使得为测试提取方法和类变得非常容易。

请参阅我在http://softwarecorner.wordpress.com/上的博客文章,了解有关为测试排除依赖关系的更多信息。

于 2008-11-17T12:32:42.953 回答
73

我正在使用Mock 的补丁装饰器:

from mock import patch

[...]

@patch('urllib.urlopen')
def test_foo(self, urlopen_mock):
    urlopen_mock.return_value = MyUrlOpenMock()
于 2010-03-06T15:31:31.283 回答
27

你给莫克斯看了吗?它应该做你需要的一切。这是一个简单的交互式会话,说明了您需要的解决方案:

>>> import urllib
>>> # check that it works
>>> urllib.urlopen('http://www.google.com/')
<addinfourl at 3082723820L ...>
>>> # check what happens when it doesn't
>>> urllib.urlopen('http://hopefully.doesnotexist.com/')
#-- snip --
IOError: [Errno socket error] (-2, 'Name or service not known')

>>> # OK, let's mock it up
>>> import mox
>>> m = mox.Mox()
>>> m.StubOutWithMock(urllib, 'urlopen')
>>> # We can be verbose if we want to :)
>>> urllib.urlopen(mox.IgnoreArg()).AndRaise(
...   IOError('socket error', (-2, 'Name or service not known')))

>>> # Let's check if it works
>>> m.ReplayAll()
>>> urllib.urlopen('http://www.google.com/')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.5/site-packages/mox.py", line 568, in __call__
    raise expected_method._exception
IOError: [Errno socket error] (-2, 'Name or service not known')

>>> # yay! now unset everything
>>> m.UnsetStubs()
>>> m.VerifyAll()
>>> # and check that it still works
>>> urllib.urlopen('http://www.google.com/')
<addinfourl at 3076773548L ...>
于 2008-11-17T12:49:46.103 回答
15

HTTPretty的工作方式与 FakeWeb 完全相同。HTTPretty 在套接字层工作,因此它应该可以拦截任何 python http 客户端库。它针对 urllib2、httplib2 和请求进行了实战测试

import urllib2
from httpretty import HTTPretty, httprettified


@httprettified
def test_one():
    HTTPretty.register_uri(HTTPretty.GET, "http://yipit.com/",
                           body="Find the best daily deals")

    fd = urllib2.urlopen('http://yipit.com')
    got = fd.read()
    fd.close()

    assert got == "Find the best daily deals"
于 2012-11-08T20:01:37.407 回答
9

如果您甚至不想加载模块:

import sys,types
class MockCallable():
  """ Mocks a function, can be enquired on how many calls it received """
  def __init__(self, result):
    self.result  = result
    self._calls  = []

  def __call__(self, *arguments):
    """Mock callable"""
    self._calls.append(arguments)
    return self.result

  def called(self):
    """docstring for called"""
    return self._calls

class StubModule(types.ModuleType, object):
  """ Uses a stub instead of loading libraries """

  def __init__(self, moduleName):
    self.__name__ = moduleName
    sys.modules[moduleName] = self

  def __repr__(self):
    name  = self.__name__
    mocks = ', '.join(set(dir(self)) - set(['__name__']))
    return "<StubModule: %(name)s; mocks: %(mocks)s>" % locals()

class StubObject(object):
  pass

进而:

>>> urllib = StubModule("urllib")
>>> import urllib # won't actually load urllib

>>> urls.urlopen = MockCallable(StubObject())

>>> example = urllib.urlopen('http://example.com')
>>> example.read = MockCallable('foo')

>>> print(example.read())
'foo'
于 2011-07-11T00:12:41.583 回答
8

处理此问题的最佳方法可能是拆分代码,以便处理页面内容的逻辑与获取页面的代码分开。

然后将 fetcher 代码的实例传递给处理逻辑,然后您可以轻松地将其替换为模拟 fetcher 以进行单元测试。

例如

class Processor(oject):
    def __init__(self, fetcher):
        self.m_fetcher = fetcher

    def doProcessing(self):
        ## use self.m_fetcher to get page contents

class RealFetcher(object):
    def fetchPage(self, url):
        ## get real contents

class FakeFetcher(object):
    def fetchPage(self, url):
        ## Return whatever fake contents are required for this test
于 2008-11-17T12:23:30.413 回答
3

最简单的方法是更改​​您的函数,使其不必使用 urllib.urlopen。假设这是您的原始功能:

def my_grabber(arg1, arg2, arg3):
    # .. do some stuff ..
    url = make_url_somehow()
    data = urllib.urlopen(url)
    # .. do something with data ..
    return answer

添加一个参数,该参数是用于打开 URL 的函数。然后你可以提供一个模拟函数来做你需要的任何事情:

def my_grabber(arg1, arg2, arg3, urlopen=urllib.urlopen):
    # .. do some stuff ..
    url = make_url_somehow()
    data = urlopen(url)
    # .. do something with data ..
    return answer

def test_my_grabber():
    my_grabber(arg1, arg2, arg3, urlopen=my_mock_open)
于 2008-11-17T12:26:06.337 回答
0

添加到克林特米勒的答案,要做到这一点,我必须创建一个实现读取方法的假类,如下所示:

class FakeURL:
    def read(foo):
        return '{"some":"json_text"}'

然后存根 urllib2.open:

# Stub out urllib2.open.
def dummy_urlopen(foo, bar, baz):
  return FakeURL()
urllib2.urlopen = dummy_urlopen
于 2019-01-25T10:03:24.247 回答