3

我正在构建一个必须与 Google Contacts API 交互并检索经过身份验证的用户的联系人列表的网络应用程序,但我得到了

ClientException in RequestException.php line 89:
Client error response [url] https://www.google.com/m8/feeds/contacts/ambermphatic@gmail.com/full?prettyPrint=false [status code] 403 [reason phrase] Forbidden

这是我的 AuthenticateUser.php,其中包含了 getContactList 函数,我正在尝试向 Google 服务器发出 Guzzle 请求,并通过将其存储在会话变量中来设法发送正确的访问令牌,但我仍然被禁止回复 :

<?php
namespace App;
use Laravel\Socialite\Contracts\Factory as Socialite;
use App\Repositories\UserRepository;
use Illuminate\Contracts\Auth\Guard;


class AuthenticateUser {

    /**
     * @var UserRepository
     */
    private $users;
    /**
     * @var Socialite
     */
    private $socialite;
    /**
     * @var Guard
     */
    private $guard;

    private $token;

    public function __construct(UserRepository $users, Socialite $socialite, Guard $guard)
    {

        $this->users = $users;
        $this->socialite = $socialite;
        $this->guard = $guard;
    }


    /**
     * @param $hasCode
     * @param AuthenticateUserListener $listener
     * @return mixed
     */
    public function execute($hasCode, AuthenticateUserListener $listener)
    {

        if ( ! $hasCode ) return $this->getAuthorizationFirst();

        $var = $this->getGoogleUser();

        $user = $this->users->findByUsernameOrCreate($var);

        \Session::put('token', $var->token );

        \Auth::login($user, true);

        return $listener->userHasLoggedIn($user);

    }

    public function logout()
    {

        \Auth::logout();

        return redirect('/');


    }

    private function getAuthorizationFirst()
    {

        return \Socialize::with('google')->redirect();

    }

    private function getGoogleUser()
    {

        return \Socialize::with('google')->user();
    }

    public function getContactList()
    {

        $client = new \GuzzleHttp\Client();

        $email = \Auth::user()->email;

        $token = \Session::get('token');

        $json = $client->get('https://www.google.com/m8/feeds/contacts/'. $email . '/full', [
            'query' => [
                'prettyPrint' => 'false',
            ],
            'headers' => [
                'Accept' => 'application/json',
                'Authorization' => 'Bearer ' . $token ,
            ],
        ]);

        dd($json);

        return $json;

    }
}

这是我的 AuthController.php

<?php namespace App\Http\Controllers;

use App\AuthenticateUser;
use App\AuthenticateUserListener;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use Laravel\Socialite\Two\GoogleProvider as Google;

use Illuminate\Http\Request;

class AuthController extends Controller implements AuthenticateUserListener
{

    public function login(AuthenticateUser $authenticateUser, Request $request){

       return $authenticateUser->execute($request->has('code'), $this);
    }

    public function userHasLoggedIn($user)
    {

        return redirect('/');
    }

    public function logout(AuthenticateUser $authenticateUser){


        return $authenticateUser->logout();

    }

    public function getContactList(AuthenticateUser $authenticateUser)
    {
        $response = $authenticateUser->getContactList();

        dd($response);
    }
}

这是我的 MainController.php

<?php namespace App\Http\Controllers;

use App\Http\Requests;
use App\Http\Controllers\Controller;

use Illuminate\Http\Request;

class MainController extends Controller {


    public function index()
    {
        if (\Auth::check()) return redirect('google_welcome');
        return redirect('google_login');
    }

    public function first()
    {
        return view('google_login');
    }

    public function back()
    {
        $user = \Auth::user();
        return view('google_welcomeback')->with('user', $user);
    }

}

我对 PHP 和 Laravel 世界还很陌生,尝试立即使用 Google API 和包(例如使用 oAuth 2 的社交名流)有什么意义。我真的很难充分利用我有限的知识,但还没有真正找到网上有很多文档,问题是我的雇主暗示我要么必须尽快完成这项工作,要么他会告诉我出路...

4

2 回答 2

3

我今天遇到了同样的问题。调试社交名流我发现获取授权令牌调用谷歌存在问题。

最后结果证明只是客户端机密复制错误地粘贴到配置中。

要发现问题的真正根源,您可以尝试以下命令:

curl -v -d grant_type=authorization_code -d client_id="<YOUR_ID_HERE>" -d client_secret="<YOUR_SECRET_HERE>" -d code="<CODE_HERE>" -d redirect_uri="<YOUR_CALLBACK_URI_HERE>" https://accounts.google.com/o/oauth2/token

您已经拥有的客户端 ids/secrets/uris 和代码可以通过调试器获取或在 ./vendor/laravel/socialite/src/Two/GoogleProvider.php 中添加一些调试打印 - 例如在 getAccessToken($code) 方法中。

对我来说,它得到了真正的答案:

{
  "error" : "invalid_client",
  "error_description" : "The OAuth client was not found."
}

一旦你解决了这个问题,还有一个没有记录的警告——社交名流需要你的谷歌应用启用谷歌+ API。这可以在以下位置完成:https ://console.developers.google.com

于 2015-03-30T11:00:47.823 回答
2

我已经设法度过并最终克服了那个错误,将我的 getContactList 函数更改为以下内容并添加了正确的范围:

 public function getContactList()
    {
        $config = [
            'client_id' => env('CLIENT_ID', ''),
            'client-secret' => env('CLIENT_SECRET', ''),
        ];

        $client = new \GuzzleHttp\Client($config);

        $email = \Auth::user()->email;

        $token = \Session::get('token');

        $json = $client->get('https://www.google.com/m8/feeds/contacts/default/full/',  [

            'headers' => [

                'Authorization' => 'Bearer ' . $token,

            ],
        ]);

        dd($json);

        return $json;
于 2015-03-30T15:39:02.217 回答