我尝试使用@staticmethod 和@classmethod 创建接口。声明类方法很简单。但我找不到声明静态方法的正确方法。
考虑类接口及其实现:
#!/usr/bin/python3
from zope.interface import Interface, implementer, verify
class ISerializable(Interface):
def from_dump(slice_id, intex_list, input_stream):
'''Loads from dump.'''
def dump(out_stream):
'''Writes dump.'''
def load_index_list(input_stream):
'''staticmethod'''
@implementer(ISerializable)
class MyObject(object):
def dump(self, out_stream):
pass
@classmethod
def from_dump(cls, slice_id, intex_list, input_stream):
return cls()
@staticmethod
def load_index_list(stream):
pass
verify.verifyClass(ISerializable, MyObject)
verify.verifyObject(ISerializable, MyObject())
verify.verifyObject(ISerializable, MyObject.from_dump(0, [], 'stream'))
输出:
Traceback (most recent call last):
File "./test-interface.py", line 31, in <module>
verify.verifyClass(ISerializable, MyObject)
File "/usr/local/lib/python3.4/dist-packages/zope/interface/verify.py", line 102, in verifyClass
return _verify(iface, candidate, tentative, vtype='c')
File "/usr/local/lib/python3.4/dist-packages/zope/interface/verify.py", line 97, in _verify
raise BrokenMethodImplementation(name, mess)
zope.interface.exceptions.BrokenMethodImplementation: The implementation of load_index_list violates its contract
because implementation doesn't allow enough arguments.
我应该如何在这个接口中正确声明静态方法?