3

我有一个Applescript,它给了我一个结果。但我无法将值解开为字符串,因此我可以使用它。

var set: String = "set windowTile to \"\"\n"
var tell: String = "tell application \"System Events\"\n"
var setFrontApp: String = "set frontApp to first application process whose frontmost is true\n"
var setFrontAppName: String = "set frontAppName to name of frontApp\n"
var tellProcces: String = "tell process frontAppName\n"
var tellFirst: String = "tell (1st window whose value of attribute \"AXMain\" is true)\n"
var setWindowTitle: String = "set windowTitle to value of attribute \"AXTitle\"\n"
var endTellFirst: String = "end tell\n"
var endTellProcess: String = "end tell\n"
var endTell: String = "end tell"
var startAtLoginScript: NSAppleScript = NSAppleScript(source: set + tell + setFrontApp + setFrontAppName + tellProcces + tellFirst + setWindowTitle + endTellFirst + endTellProcess + endTell)     
var scriptResult:NSAppleEventDescriptor = startAtLoginScript.executeAndReturnError(errorInfo)!

NSLog ("%@",  scriptResult)

NSLog 看起来像这样:

2015-03-14 15:15:14.001 test[7315:161881] 
<NSAppleEventDescriptor:'utxt'("test.swift")>

实际结果是一个字符串“test.swift”。我怎样才能解开/解析这个结果?

我试着添加这个:

var number:Int = 1
let result = scriptResult.descriptorAtIndex(number)

我也尝试使用该方法descriptorForKeyword(<#keyword: AEKeyword#>),但我不知道设置 AEKeyword 的热度。

4

2 回答 2

2

您可以使用if…let语法同时检查结果nil并在它有值时将其解包。

descriptorAtIndex不会得到你想要的,因为描述符不包含utxt条目——它一个utxt条目(你可以通过打印出来看到这一点,result.descriptorType它会给你'utxt'的四字符代码)。所以stringValue应该为您提供纯字符串值,但它是可选的,因此您可以在相同的let.

如果您只想输出数据,println将在没有时间戳等的情况下执行(实际上NSLog还会将错误记录到您可能不想要的控制台)

import Foundation

let script = "\n".join([
  "set windowTile to \"\"",
  "tell application \"System Events\"",
    "set frontApp to first application process whose frontmost is true",
    "set frontAppName to name of frontApp",
    "tell process frontAppName",
      "tell (1st window whose value of attribute \"AXMain\" is true)",
        "set windowTitle to value of attribute \"AXTitle\"",
      "end tell",
    "end tell",
  "end tell",
])

var errorInfo: NSDictionary?

if let script = NSAppleScript(source: script),
   let result = script.executeAndReturnError(&errorInfo),
   let text = result.stringValue {
    println(text)
}
else if let error = errorInfo {
    println(error)
}
else {
    println("Unexpected error while executing script")
}
于 2015-03-14T15:11:24.533 回答
1

scriptResult.stringValue(), 也许?(我很少使用 Swift。)

于 2015-03-14T14:36:11.980 回答